Answer:
1000N,4.48m/s
Explanation:
Height(h) = 1m
P. E = 1000J
P. E = mass x acceleration due to gravity x height
Acceleration due to gravity = 10m/s
P. E = mgh
Where weight = mg
P. E = weight x height
Weight = P. E / height
Weight = 1000 / 1
Weight. 1000N
b) as he leaves the ground P. E = K. E
P. E = 1/2 mv2
P. E = 1000 , mass = weight / 10
Mass =1000/10 = 100kg
P. E = 1/2 mv2
1000 = 1/2 x 100 x v2
Multiply both sides by 2
1000 x 2 = 100 x v2
V2 = 2000/ 100
V2 =20
Square root both sides
V = square root of 20
V = 4.48m/s
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Answer:
Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Explanation:
Answer:
0.12
Explanation:
The acceleration due to gravity of a planet with mass M and radius R is given as:
g = (G*M) / R²
Where G is gravitational constant.
The mass of the planet M = 3 times the mass of earth = 3 * 5.972 * 10^24 kg
The radius of the planet R = 5 times the radius of earth = 5 * 6.371 * 10^6 m
Therefore:
g(planet) = (6.67 * 10^(-11) * 3 * 5.972 * 10^24) / (5 * 6.371 * 10^6)²
g(planet) = 1.18 m/s²
Therefore ratio of acceleration due to gravity on the surface of the planet, g(planet) to acceleration due to gravity on the surface of the planet, g(earth) is:
g(planet)/g(earth) = 1.18/9.8 = 0.12
Answer:
x_{cm} = 4.644 10⁶ m
Explanation:
The center of mass is given by the equation
= 1 / 
∑ 
Where M_{total} is the total masses of the system, 
is the distance between the particles and 
is the masses of each body
Let's apply this equation to our problem
M = Me + m
M = 5.98 10²⁴ + 7.36 10²²
M = 605.36 10²² kg
Let's locate a reference system located in the center of the Earth
Let's calculate
x_{cm} = 1 / 605.36 10²² [Me 0 + 7.36 10²² 3.82 10⁸]
x_{cm} = 4.644 10⁶ m
the electrons shared between the oxygen and hydrogen atoms spend more time around the oxygen atom nucleus than around the hydrogen atom nucleus
