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stellarik [79]
3 years ago
12

Which is a disadvantage of storing data digitally?

Physics
2 answers:
pentagon [3]3 years ago
6 0

Answer:it’s B.

Explanation:

mrs_skeptik [129]3 years ago
5 0

Answer:

I thinks it’s b sorry if it didn’t help

Explanation:

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1. Calculati greutatea unui sac cu 5 kg de cartofi într-o zonă in care acceleratia gravitatională
harkovskaia [24]

Answer:

the weight is 49.1 N

Explanation:

The computation of the weight is shown below:

As we know that

= 5kg of potatoes × gravitational acceleration

= 5kg of potatoes × 9.82 m/s

= 49.1 N

Hence, the weight is 49.1 N

We simply applied the above formula in order to determine the weight

6 0
3 years ago
A lawnmower engine running for 20 minutes does 4560000 j of work. What is the power output of the engine
Alenkasestr [34]

<em>Answer: </em>

tim e (t) = 20 min.

            = 20 × 60 = 1200 s ,

Work ( W) = 4560000 J

                 = 4560 KJ ,

Determine:

                 Power output (P) = Work ÷ time

                                              = 4560 ÷  1200

                                         <em>   P  = 3.8 KW</em>


3 0
3 years ago
A new business should be based on an entrepreneur's individual interests because the entrepreneur must have sufficient confidenc
hammer [34]

Answer: D) dedicate as many hours as needed to the work.

Explanation:

edge 2020

8 0
3 years ago
Read 2 more answers
If an object is thrown in an upward direction from the top of a building 1.6 x 102 ft. high at an initial velocity of 21.82 mi/h
stiv31 [10]
In this case, the object is thrown upwards from the building. Therefore, it first achieves some height before its starts dropping.

Now, when going upwards
v^2 = u^2 - 2gs

Where,
v = final velocity
u = initial velocity
g = gravitational acceleration
s = height achieved from the top of he bulding

Using the values given;
v = 0 (comes into rest before it starts dropping)
u = 21.82 mi/h = 32 ft/s
g = 9.81 m/s^2 = 32.174 ft/s^2

Then,
0^2 = 32^2 - 2*32.174*s
32^2 = 2*32.174*s
s = (32^2)/(2*32.174) = 15.91 ft

After achieving that height, it starts to drop from rest to maximum velocity when it hits the ground.
Applying the same formula;
v^2 = u^2 + 2gs

Where;
v = velocity when it hits the ground
u = initial velocity, 0 ft/s as it starts from rest
s = 15.91+1.6*10^2 = 15.91+160 = 175.91 ft

Therefore,
v^2 = 0^2 + 2*32.174*175.91
v^2 = 11319.68
v = Sqrt (11319.68) = 106.39 ft/s ≈ 32.43 m/s moving downwards.
5 0
4 years ago
Read 2 more answers
A 0.075-kg arrow is fired horizontally. The bowstring exerts a force on the arrow over a distance of 0.90 m. the bow at 40 m/s.
Studentka2010 [4]

Answer:

Use work-energy to solve this

The work done by on the bowstring will be converted into kinetic energy of the arrow

so W = F*d = K = 1/2m*v^2

o v = sqrt(2*F*d/m) = sqrt(2*65N*0.90m/0.075kg) = 39.5 m/s

Explanation:

5 0
3 years ago
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