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My name is Ann [436]
3 years ago
6

Using the numbers 5 8 and 24 create a problem using no more than four operations addition subtraction multiplication division sq

uare square root cube cube root where is the solution when a solution will be in a rational number explain the wagon result of your operation is the number irrational number
Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

(\frac{24}{8})^{2} gives rational solution and \sqrt{5} gives an irrational solution.

Step-by-step explanation:

We are given the numbers 5 , 8 , 24.

Using these numbers and maximum four operations given, we need to find the problem having a rational and irrational solution.

Now, applying two operations namely division and squaring, we define the following problem having a rational solution.

i.e. (\frac{24}{8})^{2} = (\frac{12}{4})^{2} = 3^{2} = 9, being an integer, it is a rational number.

Further, applying only one operation namely square root, we define the problem having an irrational solution.

i.e. \sqrt{5} , which is an irrational number.

Hence, the problems (\frac{24}{8})^{2} gives a rational solution and \sqrt{5} gives an irrational solution.

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Answer:

(f - g)(3) = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 4x - 2

g(x) = x + 1

<u>Step 2: Find</u>

<em>Find (f - g)(x)</em>

  1. Substitute:                         (f - g)(x) = 4x - 2 - (x + 1)
  2. Distribute -1:                      (f - g)(x) = 4x - 2 - x - 1
  3. Combine like terms:         (f - g)(x) = 3x - 3

<em>Find (f - g)(3)</em>

  1. Substitute:                         (f - g)(3) = 3(3) - 3
  2. Multiply:                             (f - g)(3) = 9 - 3
  3. Subtract:                            (f - g)(3) = 6
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