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Alex73 [517]
3 years ago
11

Hemoglobin in your blood does not use elemental iron. It uses iron in the form of Fe2+(aq).

Chemistry
1 answer:
valina [46]3 years ago
3 0

Explanation:

Balanced chemical reaction equation will be as follows.

     2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)

In human body, the neutral iron changes into Fe^{2+}(aq) cation. There will be an oxidation-half reaction and a reduction-half reaction. Equations for this reaction are as follows.

Oxidation: 2Fe^{2+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + 2e^{-}[/tex] .... (1)

Reduction: 2H^{+}(aq) + 2e^{-} \rightleftharpoons H_{2}(g) ...... (2)

On adding both equation (1) and (2), the overall reaction equation will be as follows.

     2Fe^{2+}(aq) + 2H^{+}(aq) \rightleftharpoons 2Fe^{3+}(aq) + H_{2}(g)

Therefore, neutral iron is a part of Heme - b group of Hemoglobin and in an aqueous solution it dissolutes as a part of Heme group. Hence, then it becomes an Fe^{2+} cation.

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Manganese(II) oxide, lead(IV) oxide, and nitric acid react to produce permanganic acid, lead(II) nitrate, and water according to
Leokris [45]

Answer:

There will be produced:

2.97 moles HMnO4

4.45 moles Pb(NO3)2

2.97 moles H2O

Explanation:

Step 1: Data given

Manganese(II) oxide = MnO2

lead(IV) oxide = PbO2

nitric acid = HNO3

Moles of HNO3 = 8.90 moles

Step 2: The balanced equation

2MnO2 + 3PbO2 + 6HNO3 → 2HMnO4 + 3Pb(NO3)2 + 2H2O

Step 3: Calculate moles of reactants and products

For 2 moles MnO2 we need 3 moles PbO2 and 6 moles HNO3 to produce 2 moles HMnO4, 3 moles Pb(NO3)2 and 2 moles of water

For 8.90 moles of HNO3, there will react:

8.90 / 3 = 2.97 moles MnO2

8.90 / 2 = 4.45 moles PbO2

There will be produced:

8.90/3 = 2.97 moles HMnO4

8.90/2 = 4.45 moles Pb(NO3)2

8.90 / 3 = 2.97 moles H2O

7 0
3 years ago
I have to obtain an empirical formula from:
JulsSmile [24]
When finding empirical formulas decimals are fine so you wouldn't have to multiply all of them to turn into whole numbers. What you would do is divide each of those numbers by the smallest of those numbers and take the nearest whole number so if you had:

1.81 mol     .6 mol     and .3.61 mol you would divide each of those numbers by .6
and you would have 3, 1, and 6

for your problem you would divide them all by 1 and Carbon would be 2 (if your teacher normally has you round down at .5's then it would be 1)  hydrogen would be 3 and oxygen would be 1. 
C2H3O

7 0
3 years ago
Which intermolecular force would cause the highest boiling point?
finlep [7]
Hydrogen bonds.
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4 0
3 years ago
What is the density of a 19.3-gram object that displaces 12 cubed centimeters of water
KIM [24]

Answer:

1.608 g/cm3

Explanation:

Formula:

D=m/v

d= density

m= mass

v= volume

Given data:

Mass= 19.3 g

Volume= 12 cm3

The volume of water displaces by object is 12 cm³ which means that object hold the volume of 12 cm³

Now we will put the values in formula:

D=19.3 g/ 12 cm3= 1.608 g/cm3

so the density of object is 1.608 g/cm3

5 0
3 years ago
I need help with two questions.
vodomira [7]

Answer:

1) their atomic numbers

2) periodic table

8 0
3 years ago
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