Answer:1.188
⋅
10
5
1.188 Times 10 to the fifth power
Explanation:
Answer:
The major ionic constituents whose concentrations can be determined from the salinity are known as conservative substances. Their constant relative concentrations are due to the large amounts of these species in the oceans in comparison t
Answer:
sodium, Na
Explanation:
Na, is the smallest with atomic number 11 and it has one valence electron
Explanation :
According to the molecular orbital theory, the general molecular orbital configuration will be,
![(\sigma_{1s}),(\sigma_{1s}^*),(\sigma_{2s}),(\sigma_{2s}^*),(\sigma_{2p_z}),[(\pi_{2p_x})=(\pi_{2p_y})],[(\pi_{2p_x}^*)=(\pi_{2p_y}^*)],(\sigma_{2p_z}^*)](https://tex.z-dn.net/?f=%28%5Csigma_%7B1s%7D%29%2C%28%5Csigma_%7B1s%7D%5E%2A%29%2C%28%5Csigma_%7B2s%7D%29%2C%28%5Csigma_%7B2s%7D%5E%2A%29%2C%28%5Csigma_%7B2p_z%7D%29%2C%5B%28%5Cpi_%7B2p_x%7D%29%3D%28%5Cpi_%7B2p_y%7D%29%5D%2C%5B%28%5Cpi_%7B2p_x%7D%5E%2A%29%3D%28%5Cpi_%7B2p_y%7D%5E%2A%29%5D%2C%28%5Csigma_%7B2p_z%7D%5E%2A%29)
As there are 7 electrons present in nitrogen and 9 electrons in fluorine.
(a) The number of electrons present in
molecule = 7 + 9 = 16
The molecular orbital configuration of
molecule will be,
![(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,(\sigma_{2p_z})^2,[(\pi_{2p_x})^2=(\pi_{2p_y})^2],[(\pi_{2p_x}^*)^1=(\pi_{2p_y}^*)^1],(\sigma_{2p_z}^*)^0](https://tex.z-dn.net/?f=%28%5Csigma_%7B1s%7D%29%5E2%2C%28%5Csigma_%7B1s%7D%5E%2A%29%5E2%2C%28%5Csigma_%7B2s%7D%29%5E2%2C%28%5Csigma_%7B2s%7D%5E%2A%29%5E2%2C%28%5Csigma_%7B2p_z%7D%29%5E2%2C%5B%28%5Cpi_%7B2p_x%7D%29%5E2%3D%28%5Cpi_%7B2p_y%7D%29%5E2%5D%2C%5B%28%5Cpi_%7B2p_x%7D%5E%2A%29%5E1%3D%28%5Cpi_%7B2p_y%7D%5E%2A%29%5E1%5D%2C%28%5Csigma_%7B2p_z%7D%5E%2A%29%5E0)
The formula of bonding order = ![\frac{1}{2}\times (\text{Number of bonding electrons}-\text{Number of anti-bonding electrons})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%28%5Ctext%7BNumber%20of%20bonding%20electrons%7D-%5Ctext%7BNumber%20of%20anti-bonding%20electrons%7D%29)
The bonding order of
= ![\frac{1}{2}\times (10-6)=2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%2810-6%29%3D2)
(b) The number of electrons present in
molecule = 7 + 9 - 1 = 15
The molecular orbital configuration of
molecule will be,
![(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,(\sigma_{2p_z})^2,[(\pi_{2p_x})^2=(\pi_{2p_y})^2],[(\pi_{2p_x}^*)^1=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0](https://tex.z-dn.net/?f=%28%5Csigma_%7B1s%7D%29%5E2%2C%28%5Csigma_%7B1s%7D%5E%2A%29%5E2%2C%28%5Csigma_%7B2s%7D%29%5E2%2C%28%5Csigma_%7B2s%7D%5E%2A%29%5E2%2C%28%5Csigma_%7B2p_z%7D%29%5E2%2C%5B%28%5Cpi_%7B2p_x%7D%29%5E2%3D%28%5Cpi_%7B2p_y%7D%29%5E2%5D%2C%5B%28%5Cpi_%7B2p_x%7D%5E%2A%29%5E1%3D%28%5Cpi_%7B2p_y%7D%5E%2A%29%5E0%5D%2C%28%5Csigma_%7B2p_z%7D%5E%2A%29%5E0)
The bonding order of
= ![\frac{1}{2}\times (10-5)=2.5](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%2810-5%29%3D2.5)
(c) The number of electrons present in
molecule = 7 + 9 + 1 = 17
The molecular orbital configuration of
molecule will be,
![(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^2,(\sigma_{2s}^*)^2,(\sigma_{2p_z})^2,[(\pi_{2p_x})^2=(\pi_{2p_y})^2],[(\pi_{2p_x}^*)^2=(\pi_{2p_y}^*)^1],(\sigma_{2p_z}^*)^0](https://tex.z-dn.net/?f=%28%5Csigma_%7B1s%7D%29%5E2%2C%28%5Csigma_%7B1s%7D%5E%2A%29%5E2%2C%28%5Csigma_%7B2s%7D%29%5E2%2C%28%5Csigma_%7B2s%7D%5E%2A%29%5E2%2C%28%5Csigma_%7B2p_z%7D%29%5E2%2C%5B%28%5Cpi_%7B2p_x%7D%29%5E2%3D%28%5Cpi_%7B2p_y%7D%29%5E2%5D%2C%5B%28%5Cpi_%7B2p_x%7D%5E%2A%29%5E2%3D%28%5Cpi_%7B2p_y%7D%5E%2A%29%5E1%5D%2C%28%5Csigma_%7B2p_z%7D%5E%2A%29%5E0)
The bonding order of
= ![\frac{1}{2}\times (10-7)=1.5](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%2810-7%29%3D1.5)