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Galina-37 [17]
3 years ago
15

What is true about warm, saturated air?

Chemistry
1 answer:
prisoha [69]3 years ago
3 0

Answer:

It contains more water vapor than cold air

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a chemist determined by measurements that 0.015 moles of tungsten participated in a chemical reaction. Calculate the mass of tun
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Answer: 0.84g

Explanation:

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Please help!!! I will mark you brainiest!!!
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Answer:

Some positive effects of using synthetic plastic is that scientist can make it softer and biodegradable so that nature can break it down and destroy it so it won't affect the environment. And scientist can also make stronger and tougher in products so they can last longer.

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Given the partial equation: NO3− Pb2 → NO2 Pb4 , balance the reaction in acidic solution using the half-reaction method and fill
Fed [463]

Answer : The balanced reaction in acidic solution is,

2NO_3^-+1Pb^{2+}+4H^+\rightarrow 2NO_2+1Pb^{4+}+2H_2O

Explanation :

The given partial equation is,

NO_3^-+Pb^{2+}\rightarrow NO_2+Pb^{4+}

First we have to separate into half reaction. The two half reactions are:

NO_3^-\rightarrow NO_2

Pb^{2+}\rightarrow Pb^{4+}

Now we have to balance the half reactions in acidic medium, we get:

NO_3^-+2H^++1e^-\rightarrow NO_2+H_2O       ............(1)

Pb^{2+}\rightarrow Pb^{4+}+2e^-     ............(2)

Now we have to balance the electrons of the half reactions. When we are multiplying the equation (1) by 2, we get

2NO_3^-+4H^++2e^-\rightarrow 2NO_2+2H_2O  ...........(3)

Now we have to add both the half reactions (2) and (3), we get the final balanced chemical reaction.

2NO_3^-+1Pb^{2+}+4H^+\rightarrow 2NO_2+1Pb^{4+}+2H_2O

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3 years ago
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3 years ago
A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container. Since Kr is expensive, you wish to re
Elena-2011 [213]

Answer:

a) 24.31 g

b) 16.69 g

Explanation:

A mixture of CO2 and Kr weighs 41.0 g and exerts a pressure of 0.729 atm in its container.

After the CO2 is completely removed by absorption with NaOH(s), the pressure in the container is 0.193 atm.

Therefore, Pressure of Kr = 0.193 atm

Pressure of CO2  = 0.729 - 0.193 = 0.536 atm

Their mole fraction can be also determined as follows:

CO2 = \frac{Presssure due to CO_2}{Total pressure}

CO2 = \frac{0.536}{0.729}

= 0.735

Also; for Kr ; we have

Kr = \frac{0.193}{0.729}

Kr = 0.265

Molar mass of CO2 = 44 g/mol

Molar mass of Kr = 83.78 g/mol

Mass of CO2 = mole fraction * molar mass = 0.735 * 44 = 32.34

Mass of Kr = 0.265 *  83.78 = 22.20

Total mass = 32.34 +22.20 = 54.54

The Percentage of gas in mixture is  as follows:

% CO2 = \frac{32.34}{54.54}* 100 %

= 0.5930

= 59.30%  

(a) Mass of CO2 in mixture = 0.5930* 41 g = 24.31 g

% Kr =\frac{22.20}{ 54.54} * 100 %

= 0.407

= 40.70 %

(b) Mass of Kr in mixture = 0.407 * 41 = 16.69 g

4 0
4 years ago
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