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nignag [31]
3 years ago
15

Convert 1.75 g/mL to the unit g/m3. Answer Choices: (1.75 x 106 g/m3), (1.75 x 102 g/m3), (1.75 x 10-2 g/m3), (1.75 x 10-6 g/m3)

Chemistry
1 answer:
Marta_Voda [28]3 years ago
4 0
 Answer : 1750000g/cm3
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What mass of sodium bicarbonate do you start with
valentina_108 [34]

Answer:

84.007 g/mol

Explanation:

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5 0
3 years ago
What is the balanced equation and type of reaction for: <br> Copper metal+aqueous silver nitrate
Gnesinka [82]

Answer:

Cu(s) + 2AgNO3(aq)→Cu(NO3)2(aq)+2Ag(s)

This chemical equation means:

One mole of solid copper plus two moles of aqueous silver nitrate produce one mole of copper(II) nitrate plus two moles of solid silver.

This is a single replacement reaction in which the metal copper replaces the metal silver.

3 0
2 years ago
If 15.00 mL of 0.0100 M Ca(IO3)2 solution are mixed with 0.500 g KI, what is the theoretical yield (in grams) of I2?
n200080 [17]

The theoretical yield of I2 in the reaction would be 0.23 g

<h3>Theoretical yield</h3>

This refers to the stoichiometric yield of a reaction.

From the equation of the reaction:

Ca(IO3)2 + 10 KI + 12 HCl → 6 I2 + CaCl2 + 10 KCl + 6 H2O

The mole ratio of Ca(IO3)2 and I2 is 1: 6

Mole of 15.00 mL, 0.0100 M Ca(IO3)2 = 15/1000 x 0.0100

                                                              = 0.00015 mole

Equivalent mole of I2 = 0.00015 x 6

                                      = 0.009 mole

mass of 0.0009 I2 = 0.0009 x 253.809

                                = 0.23 g

More on stoichiometric calculations can be found here: brainly.com/question/6907332

8 0
2 years ago
One problem with elimination reactions is that mixtures of products are often formed. For example, treatment of 2-bromo-2-methyl
NikAS [45]

Answer:

Structures are given below.

Explanation:

  • Treatment of 2-bromo-2-methylbutane with KOH in ethanol will give elimination of HBr through E2 mechanism.
  • H atoms adjacent to Br will be eliminated.
  • 2-bromo-2-methylbutane has two possible adjacent H atoms that can be eliminated giving mixture of products.
  • Product of this elimination reaction is alkene. Here saytzeff fule is followed during elimination. So most substituted alkene will be major product.
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5 0
2 years ago
Of the five salts listed below, which has the highest concentration of its cation in water? assume that all salt solutions are s
Zigmanuir [339]
First of all, I need to know what these five salts are. Luckily, I found a similar problem from another website which is shown in the attached picture. The Ksp is the solubility product constant. It follows the formula:

Ksp = [cation concentration]ᵃ[anion concentration]ᵇ
where a and b are the subscripts of the metal and nonmetal, respectively. 

For the solutions ahead, let x be the concentration of the cation.

A.  The formula is PbCr₂O₄.
2.8×10⁻¹³ = [x][x]
Solving for x, x = 5.29×10⁻⁷ M

B. The formula is Co(OH)₂. 
 1.3×10⁻¹⁵ = [x][x]²
Solving for x, x = 1.09×10⁻⁵ M

C. The formula is CoS. 
 5×10⁻²² = [x][x]
Solving for x, x = 2.24×10⁻¹¹ M

D. The formula is Cr(OH)₃. 
 1.6×10⁻³⁰ = [x][x]³
Solving for x, x = 3.56×10⁻⁶ M

E. The formula is Ag₂S. 
 6×10⁻⁵¹ = [x]²[x]
Solving for x, x = 1.82×10⁻¹⁷ M

<em>Thus,the highest concentration is letter B, Cobalt (II) Hydroxide.</em>

5 0
2 years ago
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