<span>Matter is c) something that has mass and occupies space. Everything in our known universe takes up space, and everything is made up of matter. Matter as a concept is not something that can have any unit of measurement put upon it. </span>
The strength of the gravitational field is given by:
![g= \frac{GM}{r^2}](https://tex.z-dn.net/?f=g%3D%20%5Cfrac%7BGM%7D%7Br%5E2%7D%20)
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.
In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
![r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m](https://tex.z-dn.net/?f=r%3DR%2Bh%3D6370%20km%2B300%20km%3D6670%20km%3D%206.67%20%5Ccdot%2010%5E%7B6%7D%20m)
And now we can use the previous equation to calculate the field strength at that altitude:
![g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(6.67 \cdot 10^6 m)^2} = 8.95 m/s^2](https://tex.z-dn.net/?f=g%3D%20%5Cfrac%7BGM%7D%7Br%5E2%7D%3D%20%5Cfrac%7B%286.67%20%5Ccdot%2010%5E%7B-11%7D%20m%5E3%20kg%5E%7B-1%7D%20s%5E%7B-2%7D%29%285.97%20%5Ccdot%2010%5E%7B24%7D%20kg%29%7D%7B%286.67%20%5Ccdot%2010%5E6%20m%29%5E2%7D%20%20%3D%208.95%20m%2Fs%5E2)
And we can see this value is a bit less than the gravitational strength at the surface, which is
![g_s = 9.81 m/s^2](https://tex.z-dn.net/?f=g_s%20%3D%209.81%20m%2Fs%5E2)
.
Power can be defined as the rate at which work is accomplished.
Option D is the correct answer.
<h3>
</h3><h3>
Power </h3>
The work done by an object in a given time interval is called the power of that object.
Suppose an external force F is applied to any object for the time interval T seconds. Due to this external force, the object will perform some amount of work for the time T seconds. This work W done by the object for the time interval T seconds is called the power of that object.
Power can be defined in mathematical term which is given below.
![P = \dfrac {W}{T} \;\rm Watts](https://tex.z-dn.net/?f=P%20%3D%20%5Cdfrac%20%7BW%7D%7BT%7D%20%5C%3B%5Crm%20Watts)
Thus the power can also be defined as the work done by the object per unit time interval.
Hence we can conclude that option D is the correct answer.
To know more about power, follow the link given below.
brainly.com/question/1618040.
First we have to calculate the time taken to travel the distance 30 m, is
.
Now from equation of motion,
![v = u + at](https://tex.z-dn.net/?f=v%20%3D%20u%20%2B%20at)
Given,
.
As object starts from rest, so u = 0.
Substituting these values in above equation, we get
.
Thus, the acceleration is ![3.33 \ m/s^2](https://tex.z-dn.net/?f=3.33%20%5C%20m%2Fs%5E2)