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Leona [35]
3 years ago
7

The neutron is located in the what part of the atom

Chemistry
2 answers:
Lemur [1.5K]3 years ago
6 0

Answer: Center of the atom

Explanation: Electrons are found in shells or orbitals that surround the nucleus of an atom. Protons and neutrons are found in the nucleus. They group together in the center of the atom.

torisob [31]3 years ago
4 0

Answer:

in the middle

Explanation:

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What are the evidences for suspecting the presence of waves?
Vsevolod [243]

Answer:

Well,

Conducting rods are good for detecting oscillating electric fields and conducting loops are good for detecting the presence of radio waves.  

5 0
3 years ago
How many moles (of molecules or formula units) are in each sample? 79.34 g cf2cl2?
Alona [7]
From the periodic table:
molecular mass of carbon = 12 grams
molecular mass of fluorine = 18.99 grams
molecular mass of chlorine = 35.5 grams
Therefore:
one mole of CF2Cl2 = 12 + 2(18.99) + 2(35.5) = 120.98 grams
Therefore, we can use cross multiplication to find the number of moles in 79.34 grams as follows:
mass = (79.34 x 1) / 120.98 = 0.6558 moles

Now, one mole contains 6.022 x 10^23 molecules, therefore:
number of molecules in 0.65548 moles = 0.6558 x 6.022 x 10^23
                                                              = 3.949 x 10^23 molecules
7 0
3 years ago
The change in time for the first quarter is
Flura [38]

Answer:

2.34

Explanation:

6 0
3 years ago
Read 2 more answers
How do I do this and what are the answers?
vodka [1.7K]
I cannot see your question to help you... sorry
6 0
3 years ago
A coffee-cup calorimeter initially contains 125 g water at 24.28C. Potassium bromide (10.5 g), also at 24.28C, is added to the w
iren2701 [21]

Answer:

The solution is given below

Explanation:

Heat, q= mc∆T

q= 125g x 4.18 J/g∙°C x (21.18x- 24.28) °C

q=  -1619.75J

NEGATIVE SIGN INDICATES THAT HEAT IS ABSORBED.

Enthalpy Change, ∆H = 1619.75 7/ 10.5 g

                                     = 154.26 J/g

No. of moles of KBr = Mass of KBr/ Molecular Weight of KBr

                                =10.5g/119gmol-1

                                =0.088 mol

∆H= 1619.75 J/ 0.088 mol

      = 18.41 kJ/mol  

6 0
3 years ago
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