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3 years ago

Why is cellulose so difficult for most animals to digest?

2 answers:

5 0

Cellulose is so difficult for most animals to digest because they don’t have the proper enzyme to break the bonds between subunits.

Further explanation

Cellulose

It is a polysaccharide compound which is difficult to be digested by animals because they don’t have the enzyme needed to break it. It has many monosaccharide molecules bind together by glycosidic bond.

Glycosidic bond

It is a covalent bond. It is formed between two monosaccharide with the removal of one water molecule. It is of two types, Alpha (between C-1 of one monosaccharide and C-2 of other monosaccharide) and beta (also between the C-1 of one monosaccharide and C-2 of another monosaccharide). Enzymes are required for breakdown of cellulose. In our body various enzymes are present for the breakdown of carbohydrates but these enzymes can never digest cellulose. Our enzymes are unable to break beta glycosidic bond but they can break the alpha glycosidic bond. A bond is present in glycogen and starch so these can be digested by human beings. It is thought that such enzymes are produced by vermiform appendix. In herbivores the enzymes which are required for the breakdown of cellulose are present in their digestive tracts so they can digest cellulose.

Animal which can digest cellulose

Grazing animals like cattle can digest cellulose because they have symbiotic bacteria in their intestine and these bacteria hep them in digestion because of special enzymes in them.

Answer details

Subject: Chemistry

Level: High school

Keywords

Cellulose
Glycosidic bond
Animal which can digest cellulose

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NNADVOKAT [17]3 years ago

3 0

The answer is C .Cellulose is a long chain of glucose and to be able to use any of the energy stored in them an organism must break it down into single glucose molecules, and this is why most animals go for a different diet. The chain is very difficult to break down and must be treated with concentrated acids at high temperature. This is a hard task to do and often time needs many stomachs.

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siniylev [52]

Answer:

268.3 m/sec

Explanation:

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4 years ago

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8

Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is $pK_a =7.82$

Explanation:

From the question we are told

The volume of base is $V_B = 26.mL = 0.0260L$

The pH of solution is $pH = 7.82$

The concentration of the acid is $C_A = 0.1M$

From the pH we can see that the titration is between a strong base and a weak acid

Let assume that the the volume of acid is $V_A = 18mL= 0.018L$

Generally the concentration of base

$C_B = \frac{C_AV_A}{C_B}$

Substituting value

$C_B = \frac{0.1 * 0.01800}{0.0260}$

$C_B= 0.0692M$

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

$HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}$

Now before the reaction the number of mole of base is

$No \ of \ moles[N_B] = C_B * V_B$

Substituting value

$N_B = 0.01300 * 0.0692$

$= 0.0009 \ moles$

Now before the reaction the number of mole of acid is

$No \ of \ moles = C_B * V_B$

Substituting value

$N_A = 0.01800 *0.1$

$= 0.001800 \ moles$

Now after the reaction the number of moles of base is zero i.e has been used up

this mathematically represented as

$N_B ' = N_B - N_B = 0$

The number of moles of acid is

$N_A ' = N_A - N_B$

$= 0.0009\ moles$

The pH of this reaction can be mathematically represented as

$pH = pK_a + log \frac{[base]}{[acid]}$

Substituting values

$7.82 = pK_a +log \frac{0.0009}{0.0009}$

$pK_a =7.82$

8 0

3 years ago

How many grams N2F4 can be produced from 225 g F,?

zavuch27 [327]

Answer:

308 g

Explanation:

Data given:

mass of Fluorine (F₂) = 225 g

amount of N₂F₄ = ?

Solution:

First we look to the reaction in which Fluorine react with Nitrogen and make N₂F₄

Reaction:

2F₂ + N₂ -----------> N₂F₄

Now look at the reaction for mole ratio

2F₂ + N₂ -----------> N₂F₄

2 mole 1 mole

So it is 2:1 mole ratio of Fluorine to N₂F₄

As we Know

molar mass of F₂ = 2(19) = 38 g/mol

molar mass of N₂F₄ = 2(14) + 4(19) =

molar mass of N₂F₄ = 28 + 76 =104 g/mol

Now convert moles to gram

2F₂ + N₂ -----------> N₂F₄

2 mole (38 g/mol) 1 mole (104 g/mol)

76 g 104 g

So,

we come to know that 76 g of fluorine gives 104 g of N₂F₄ then how many grams of N₂F₄ will be produce by 225 grams of fluorine.

Apply unity formula

76 g of F₂ ≅ 104 g of N₂F₄

225 g of F₂ ≅ X of N₂F₄

Do cross multiplication

X of N₂F₄ = 104 g x 225 g / 76 g

X of N₂F₄ = 308 g

So,

308 g N₂F₄ can be produced from 225 g F₂

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3 years ago

What is the maximum amount in moles of P2O5 that can theoretically be made from 176 g of O2 and excess phosphorus?

Strike441 [17]

Answer:

2.60 mol2

Explanation:

2.60mol2 is ur answer

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3 years ago

According to Boyle’s law, when the pressure on a gas increases at constant temperature, its volume

gladu [14]

The answer is c. decreases. The gas law has a rule of P1V1=P2V2. So when the pressure of this gas increases, the volume will decrease.

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3 years ago

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