Answer:
(i) the other two sides are 6 and 6
(ii) the other two sides are 
Step-by-step explanation:
(i) Sine: sin(θ) = Opposite ÷ Hypotenuse
Cosine: cos(θ) = Adjacent ÷ Hypotenuse
Tangent: tan(θ) = Opposite ÷ Adjacent
Here adjacent side = 6
opposite side = d
angle = 45°
other angles are 90° and 45°
tan (45) = Opposite ÷ Adjacent
1 = d ÷ 6
∴ d = 6 × 1 = 6
so opposite side = 6
Hypotenuse ² = opposite side ² + adjacent side²
= 6² + 6²
= 36 + 36
= 72
hypotenuse = 
= 6
the other two sides are 6 and 6
(ii) here adjacent side = 4√3
angle = 30°
other angles are 90° and 60°
opposite side = d
tan ( 30) = opposite ÷ adjacent
= d ÷ 4√3
= d × (
)
3 d = 4
therefore d = 
therefore opposite side = 
Hypotenuse ² = opposite side ² + adjacent side²
=(
)² +(
)²
= 
therefore hypotenuse = 
=
the other two sides are 
N + 2 = 13
-2 -2
n = 11
I hope this helps!
To do this, you must use the order of operations.
3·2=6
6+4=10
Now to solve (-)x.
Since -x comes in front of 4, you must make your equation:
-x+10
Nothing is written for x, so now, you have the answer.
-x+10
Answer:
4
Step-by-step explanation:
If Judge is x years old and Eden is 6 years older, then Eden is x + 6 years old.
The second part tells us that Eden will be twice as old as Judge in two years.
This means that in two years: (Eden's age) = 2 * (Judge's age).
Since we know that Eden's age can be represented as x + 6 and Judge's age can be represented as x, we can write this: x + 6 = 2 * x
Simplify the equation:
x + 6 = 2x
6 = x = Judge's age (in two years)
If Judge is 6 two years later, then he must be 4 now.
To check our work, we can just look at the problem. Judge is 4 years old and Eden is 6 years older than Judge (that means Eden is 10 right now). Two years later, Eden is 12 and Judge is 6, so Eden is twice as old as Judge. The answer is correct.