Explanation:
a. Write the molecular formula of the compound.
Acetaminophen contains 8 carbon atoms, 9 Hydrogen atoms, 1 Nitrogen atom and 2 Oxygen atoms.
The molecular formular is given as; C8H9NO2
b. What is the hybridization state of each C, N, and O atom?
From the image attached;
All the carbon atoms in the benzene ring has hybridization of sp2.
The carbon that is doubly bonded (carbonyl) to the oxygen has hybridization of sp2
The last carbon to the right has hybridization of sp3
The hybridization of nitrogen in the compound is sp3 hbridized.
Oxygen atom in alcohol is sp3 hybridised
Oxgen in the carbonyl group is sp2 hybridized.
Answer:
f. Sn^4+
c. second
e. Al^3+
d. third
Explanation:
This question comes from a quantitative analysis showing the flowchart of a common scheme for identifying cations.
Now, from the separation scheme, Let's assume that Sn⁴⁺ & Al³⁺ were given; Then, Yes, the separation will work.
However, there will be occurrence of precipitation after the 1st step1.
So, the <u>Sn⁴⁺</u> cation will precipitate after the <u>second </u>step. Then the <u>Al³⁺</u> cation will precipitate after the <u>third</u> step.
It will only take a small amount of helium when inflating balloons. For example, an 11" balloon only needs 0.015 m3 of helium. So it make sense, why a two feet helium tank can inflate at about 50 balloons. Also, the size tank (2 ft. high) does not define the capacity of helium it contains.
D = 21.45 g/cm³
V = 78.00 cm³
D = m / V
21.45 = m / 78.00
m = 21.45 x 78.00
m = 1673.1 g
hope this helps!
The series of reactions is:
4 NH3 + 5 O2 → 4 NO + 6 H2O <span>
6 NO + P4 → P4O6 + 3 N2
P4O6 + 6 H2O → 4 H3PO3
4 H3PO3 → PH3 + 3 H3PO4 </span>
<span>
We multiply the first equation by a number 3 and all the
other equations by number 2, so that we get:
12 NH3 + 15 O2 → 12 NO + 18 H2O
12 NO + 2 P4 → 2 P4O6 + 6 N2
2 P4O6 + 12 H2O → 8 H3PO3
8 H3PO3 → 2 PH3 + 6 H3PO4
Then the overall reaction is:
12 NH3 + ... → 2 PH3 + ...
</span>
<span>So calculating for PH3:
<span>(1.10 g NH3) / (17.0306 g NH3/mol) x (2/12) x (33.9976 g
PH3/mol) = 0.366 g PH3</span></span>
