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AysviL [449]
3 years ago
12

The________ cation will precipitate after the_________ step. Then the _________cation will precipitate after the________ step.

Chemistry
1 answer:
Novay_Z [31]3 years ago
8 0

Answer:

f. Sn^4+

c. second

e. Al^3+

d. third

Explanation:

This question comes from a quantitative analysis showing the flowchart of a common scheme for identifying cations.

Now, from the separation scheme, Let's assume that Sn⁴⁺ & Al³⁺ were given; Then, Yes, the separation will work.

However, there will be occurrence of precipitation after the 1st step1.

So,  the <u>Sn⁴⁺</u> cation will precipitate after the <u>second </u>step. Then the <u>Al³⁺</u> cation will precipitate after the <u>third</u> step.

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The salt which in solution gives a pale green precipitate with sodium hydroxide solutionanda white precipitate with barium chlor
ELEN [110]

Answer:

Analytical Chemistry. The salt which in solution gives a pale green precipitate with sodium hydroxide solution and a white precipitate with barium chloride solution is : Iron (III) sulphate.

7 0
3 years ago
Read 2 more answers
If 125 mL of a 1.1 M glucose solution is diluted to 500.0 mL , what is the molarity of the diluted solution? Express your answer
Juli2301 [7.4K]

Answer:

0.28M

Explanation:

From the question given, we obtained the following information:

C1 = 1.1 M

V1 = 125mL

V2 = 500mL

C2 =?

Using the dilution formula C1V1 = C2V2, we can easily find the molarity of the diluted solution as follows:

C1V1 = C2V2

1.1 x 125 = C2 x 500

Divide both side by 500

C2 = (1.1 x 125)/500 =

C2 = 0.28M

3 0
3 years ago
Answer the following:1. A ________ is a set of elements that run from left to right. 2. Every element in the first period has __
Mrac [35]

Answer: 1. Periods 2. One, electrons 3. Two, electrons 3. Elements 4. Electrons, outermost 5. One, two 6. Seven, six

Explanation: they needed one and two electrons to complete their outer shell, so the have same valence but negative.

8 0
3 years ago
Read 2 more answers
Can all alkyl halides react with water to give alcohols?​
Margarita [4]

Not all acid-catalyzed conversions of alcohols to alkyl halides proceed through the formation of carbocations. Primary alcohols and methanol react to form alkyl halides under acidic conditions by an SN2 mechanism.

Not all acid-catalyzed conversions of alcohols to alkyl halides proceed through the formation of carbocations. Primary alcohols and methanol react to form alkyl halides under acidic conditions by an SN2 mechanism.

In these reactions the function of the acid is to produce a protonated alcohol. The halide ion then displaces a molecule of water (a good leaving group) from carbon; this produces an alkyl halide:

Again, acid is required. Although halide ions (particularly iodide and bromide ions) are strong nucleophiles, they are not strong enough to carry out substitution reactions with alcohols themselves. Direct displacement of the hydroxyl group does not occur because the leaving group would have to be a strongly basic hydroxide ion:

We can see now why the reactions of alcohols with hydrogen halides are acid-promoted.

Carbocation rearrangements are extremely common in organic chemistry reactions are are defined as the movement of a carbocation from an unstable state to a more stable state through the use of various structural reorganizational "shifts" within the molecule. Once the carbocation has shifted over to a different carbon, we can say that there is a structural isomer of the initial molecule. However, this phenomenon is not as simple as it sounds.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>

8 0
3 years ago
A gas mixture being used to simulate the atmosphere of another planet at 23°c consists of 337 mg of methane, 148 mg of argon, an
Karolina [17]

The total pressure of the mixture is 65.5 kPa.

According to Dalton's Law of Partial Pressure,

The partial pressure of gas = Mole fraction of gas × Total pressure

Total Pressure = Sum of all the gases partial pressures

The number of moles of methane is,

Moles \:  of \: methane  \: (16 g/mol) =  337 \: mg  \times  \frac{1 g}{1000 mg} \times  \frac{ 1 mol}{16 g }

= 0.021 mols

The moles of methane are 0.021 mols.

The number of moles of the argon,

Moles \:  of \: argon (40 g/mol) = 148 \:  mg  \times  \frac{  1 g}{1000 mg } \times  \frac{  1 mol}{40 g}

= 0.003 mols

The number of moles of argon is 0.003 mols.

The number of moles of nitrogen is,

Moles  \: of \: nitrogen (28 g/mol) = 296 \:  mg  \times  \frac{ 1 g}{1000 mg}  \times  \frac{  1 mol/}{28 g}

= 0.010 mols

The number of moles of nitrogen is 0.010 mols.

The total number of moles is,

= 0.021 + 0.003 + 0.010

= 0.034 mols

Mole \:  fraction =  \frac{ Moles \:  of \:  solute }{Total \:  number  \: of  \:  moles  \: of  \: soulte \:  and \:  solvent}

= \frac{  0.010 }{ 0.034}

= 0.29

0.29 \: P _{total} = 19 \:  kPa

P _{total} =  \frac{ 19  \: kPa }{0.29}

= 65.5 kPa

Therefore, the total pressure of the mixture is 65.5 kPa.

To know more about Dalton's law, refer to the below link:

brainly.com/question/14119417

#SPJ4

6 0
1 year ago
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