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AysviL [449]
2 years ago
12

The________ cation will precipitate after the_________ step. Then the _________cation will precipitate after the________ step.

Chemistry
1 answer:
Novay_Z [31]2 years ago
8 0

Answer:

f. Sn^4+

c. second

e. Al^3+

d. third

Explanation:

This question comes from a quantitative analysis showing the flowchart of a common scheme for identifying cations.

Now, from the separation scheme, Let's assume that Sn⁴⁺ & Al³⁺ were given; Then, Yes, the separation will work.

However, there will be occurrence of precipitation after the 1st step1.

So,  the <u>Sn⁴⁺</u> cation will precipitate after the <u>second </u>step. Then the <u>Al³⁺</u> cation will precipitate after the <u>third</u> step.

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Aluminum fluoride contains only aluminum and fluorine. what is the formula for this compound?
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AlF3 would be the answer
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Please help me with this thank you &lt;3
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Answer:

C and D

Explanation:

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What is the relationship between mole, Avogadro number and mass?
weeeeeb [17]

Answer:

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5 0
3 years ago
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vagabundo [1.1K]

The puppies have different colored noses because of reccesive and dominant genotypes.

Genotypes are represented by letters, capital being dominant and lowercase being recessive.

For example, lets say t = pink nose and T = black nose.

If the parents have black noses, then they will pass on T genotypes.

But, they also have hidden pink nose genotypes.

These hidden genotypes are passed on to the puppies, one of the puppies gets more black nose genotypes.

If a puppy gets tt, they will have a pink nose.

If they get TT, they will have a black nose

If they get Tt, they will also have a black nose.

Because the black nose is dominant, its more likley for the puppies to end up with a black nose.

4 0
3 years ago
C
Schach [20]

Answer:

2.74 M

Explanation:

Given data:

Mass of sodium chloride = 80.0 g

Volume of water = 500.0 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will convert the mL into L.

500.0 mL× 1 L /1000 mL =  0.5 L

In next step we will calculate the number of moles of sodium chloride.

Number of moles = mass/molar mass

Number of moles = 80.0 g/ 58.4 g/mol

Number of moles = 1.37 mol

Molarity:

M =  1.37 mol/ 0.5 L

M =  2.74 M

8 0
3 years ago
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