During the first 42 s a truck traveled at a constant speed of 8.0 m/s. Find the distance it traveled in meters. [Give answer to
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Let the stone is dropped off a cliff of height S m ft.
Given, initial velocity of the stone, u= 0 ft/s
Final velocity of the stone, v= 104 ft/s
Acceleration of the stone= Acceleration due to gravity = 32 ft/s²
Using the third equation of motion,
v² - u² = 2aS
Substituting the values we get,
S= 169 ft
Height of the cliff is 169 ft.