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OLga [1]
3 years ago
15

A space vehicle approaches a space station in orbit. The intent of the engineers is to have the vehicle slowly approach, reducin

g velocity, until a docking maneuver is completed and the vehicle is attached to the station. How does the total momentum of the docked vehicle and station compare to the momentum of each object before the docking maneuver? greater momentum same momentum less momentum
Physics
1 answer:
NeX [460]3 years ago
3 0

Answer:

c. same momentum

Explanation:

got it correct on edge2020

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A bicyclist travels 4.5 km west, then travels 6.7 km at an angle 27.0 degrees South of West. What is the magnitude of the bicycl
Dimas [21]

Answer:

<em>10.90km</em>

Explanation:

Magnitude of the total displacement is expressed using the equation

d = √dx²+dy²

dx is the horizontal component of the displacement

dy is the vertical component of the displacement

dy = -6.7sin27°

dy = -6.7(0.4539)

dy = -3.042

For the  horizontal component of the displacement

dx = -4.5 - 6.7cos27

dx = -4.5 -5.9697

dx = -10.4697

Get the magnitude of the bicyclist's total displacement

Recall that: d = √dx²+dy²

d = √(-3.042)²+(-10.4697)²

d = √9.2538+109.6146

d = √118.8684

<em>d = 10.90km</em>

<em>Hence the magnitude of the bicyclist's total displacement is 10.90km</em>

<em></em>

6 0
3 years ago
1. After a rabbit population reaches the carrying capacity of its habitat, what will most likely happen to
kifflom [539]
C) alternately increase and decrease
6 0
3 years ago
A low C (f=65Hz) is sounded on a piano. If the length of the piano wire is 2.0 m and
WITCHER [35]

Answer:

T = 676 N

Explanation:

Given that: f = 65 Hz, L = 2.0 m, and ρ = 5.0 g/m^{2} = 0.005 kg

A stationary wave that is set up in the string has a frequency of;

f = \frac{1}{2L}\sqrt{\frac{T}{M} }

⇒      T = 4L^{2}f^{2}M

Where: t is the tension in the wire, L is the length of the wire, f is the frequency of the waves produced by the wire and M is the mass per unit length of the wire.

But M = L × ρ = (2 × 0.005) = 0.01 kg/m

T = 4 × 2^{2} ×65^{2} × 0.01

   = 4 × 4 ×4225 × 0.01

   = 676 N

Tension of the wire is 676 N.

4 0
3 years ago
Suppose that a comet that was seen in 563 A.D. by Chinese astronomers was spotted again in year 1951. Assume the time between ob
Mars2501 [29]

Answer:

a=2.77*10^{13}m

R_a=5.49*10^{13}m

Explanation:

The period of the comet is the time it takes to do a complete orbit:

T=1951-(-563)=2514 years

writen in seconds:

2514years*\frac{3,154*10^7s}{1year}=7.93 *10^{10}s

Since the eccentricity is greater than 0 but lower than 1 you can know that the trajectory is an ellipse.

Therefore, if the mass of the sun is aprox. 1.99e30 kg, and you assume it to be much larger than the mass of the comet, you can use Kepler's law of periods to calculate the semimajor axis:

T^2=\frac{4\pi^2}{Gm_{sun}}a^3\\ a=\sqrt[3]{\frac{Gm_{sun}T^2}{4\pi^2} } \\a=1.50*10^{6}m

Then, using the law of orbits, you can calculate the greatest distance from the sun, which is called aphelion:

R_a=a(1+e)\\R_a=2.77*10^{13}(1.986)\\R_a=5.49*10^{13}m

8 0
3 years ago
Which is an example of making a quantitative observation?
malfutka [58]
An example of a quantitative observation is measuring the surface of an oil painting and finding its dimensions to be 12 inches by 12 inches. A quantitative observation occurs when a researcher takes a measurement that is recorded in an objective number of units.

3 0
3 years ago
Read 2 more answers
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