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OLga [1]
3 years ago
15

A space vehicle approaches a space station in orbit. The intent of the engineers is to have the vehicle slowly approach, reducin

g velocity, until a docking maneuver is completed and the vehicle is attached to the station. How does the total momentum of the docked vehicle and station compare to the momentum of each object before the docking maneuver? greater momentum same momentum less momentum
Physics
1 answer:
NeX [460]3 years ago
3 0

Answer:

c. same momentum

Explanation:

got it correct on edge2020

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The primary 40-turn coil of an ideal transformer is supplied with 120 V (rms). If the rms voltage output of the secondary coil i
Svet_ta [14]

Answer:

No. of turns in secondary coil are 5.

Transformer Type: STEP DOWN TRANSFORMER

Explanation:

The relationship of the no. of turns in transformer secondary and primary coils with their voltages is known as the turn ration. The formula for turns ratio is as follows:

Np/Ns = Vp/Vs

where,

Np = No. of turns in primary coil = 40

Ns = No. of turns in secondary coil = ?

Vp = Voltage supplied to primary coil = 120 V

Vs = Voltage output of secondary coil = 15 V

Therefore,

40/Ns = 120 V/15 V

Ns = 40/8

<u>Ns = 5</u>

TYPE OF TRANSFORMER:

Since, this transformer decreases the voltage value at the output. Hence it is a <u>STEP DOWN TRANSFORMER.</u>

7 0
4 years ago
A little girl kicks a soccer ball, it goes 10 feet then comes back to her, how is this possible??
kirza4 [7]
Its gravitational force

7 0
3 years ago
Percy Spencer was an American engineer and, while working for Raytheon, was building magnetrons for radar sets. One day, he was
Sladkaya [172]

Answer:

the answer is d

Explanation:

4 0
3 years ago
Read 2 more answers
A horizontal circular platform rotates counterclockwise about its axis at the rate of 0.841 rad/s.0.841 rad/s. You, with a mass
kvv77 [185]

Answer:

The total angular momentum of the system is 217.46\ kg-m^2/s.

Explanation:

Given that,

Angular speed = 0.841 rad/s

Mass of platform = 72.1 kg

Speed = 1.17 m/s

Mass of poodle = 20.3 kg

Mass of mutt = 18.5 kg

Distance =3/4 of the platform's radius from the center

Mass of disk = 92.5 kg

radius = 1.87 m

Angular momentum is the product of moment of inertia and angular speed.

We need to calculate the angular momentum of person

L_{person} = I\omega

L_{person}=\dfrac{1}{2}mr^2\times\omega

L_{person}=\dfrac{1}{2}\times72.1\times(\dfrac{v}{\omega})^2\times\omega

L_{person}=\dfrac{1}{2}\times72.1\times(\dfrac{1.17}{0.841})^2\times0.841

L_{person}=58.679\ kg m^2/s

We need to calculate the angular momentum of platform

L_{platform}=\dfrac{1}{2}mr^2\times\omega

Put the value into the formula

L_{platform}=\dfrac{1}{2}\times92.5\times1.87^2\times0.841

L_{platform}=136.02\ kg m^2/s

We need to calculate the angular momentum of poodle

L_{poodle}=\dfrac{1}{2}mr^2\times\omega

Put the value into the formula

L_{poodle}=\dfrac{1}{2}\times20.3\times(\dfrac{1.87}{2})^2\times0.841

L_{poodle}=7.4625\ kg m^2/s

We need to calculate the angular momentum of mutt

L_{mutt}=\dfrac{1}{2}mr^2\times\omega

L_{mutt}=\dfrac{1}{2}\times18.5\times(\dfrac{3}{4}\times1.87)^2\times0.841

L_{mutt}=15.302\ kg m^2/s

We need to calculate the total angular momentum

L=L_{person}+L_{platform}+L_{poodle}+L_{mutt}

L=58.679+136.02+7.4625+15.302

L=217.46\ kg-m^2/s

Hence, The total angular momentum of the system is 217.46\ kg-m^2/s.

3 0
3 years ago
How do you use a Beam Balance???<br>​
zepelin [54]

Explanation:

<h3>The beam balance is a device used</h3><h3> for the determination of the mass of </h3><h3>a body under gravitation. It consists </h3><h3>of a beam supported at the centre </h3><h3>by an agate knife edge resting on a</h3><h3> support moving inside a vertical </h3><h3>pillar. The beam carries a light</h3><h3>pointer which moves over a scale.</h3>
4 0
3 years ago
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