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Anika [276]
3 years ago
10

What is the balanced chemical equation for the reaction used to calculate ΔH∘f of SrCO3(s)? If fractional coefficients are requi

red, enter them as a fraction (i.e. 1/3). Indicate the physical states using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively without indicating allotropes. Use (aq) for aqueous solution. Express your answer as a chemical equation. View Available Hint(s)
Chemistry
1 answer:
Pani-rosa [81]3 years ago
6 0

Answer:

Sr(s) + C(s) + 3/2 O₂(g) → SrCO₃(s)

Explanation:

The standard enthalpy of formation (ΔH°f) is the energy involved in the formation of 1  mole of a substance from its elements in their most stable states. The chemical equation for the formation of SrCO₃(s) is the following.

Sr(s) + C(s) + 3/2 O₂(g) → SrCO₃(s)

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A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . H
maw [93]

Answer:

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

     = 5.48\times 10^{-7} \ M

M2 = 484 nM

or,

      = 4.84\times 10^{-7} \ M  

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒ M1\times V1=M2\times V2

or,

⇒            V2=\frac{M1\times V1}{M2}

By substituting the values, we get

                    =\frac{5.48\times 10^{-7}\times 61.9}{4.84\times 10^{-7}}

                    =\frac{339.212}{4.84}

                    =70.08 \ mL

7 0
3 years ago
HELPP 20+ POINTS!!!
VashaNatasha [74]
The answer is •c•
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6 0
3 years ago
What is the mass in grams of 6.022×1023 atoms of mass 16.00 amu?
skelet666 [1.2K]
You need the Avogadro's number.  I can't remember exactly the calculation.
6 0
3 years ago
What is the empirical formula for c12h24o6? what is the empirical formula for c12h24o6? ch2o cho c2h5o c2h4o cho2?
stira [4]

Empirical formula: The formula consist of proportions of the elements which is present in the compound or the simplest whole number ratios of atoms.

Now, molecular formula is equal to the product of n (ratio) and empirical formula.

Molecular formula = n\times empirical formula    (1)

molecular formula =C_{12}H_{24}O_{6} (given)

Since, 6 is the smallest subscript in above molecular formula to get the simpler whole number of atoms. Therefore, divide all the subscripts i.e. number of carbon atoms (12), number of hydrogen atoms (24) and number of oxygen atoms (6) by 6.

empirical formula becomes C_{2}H_{4}O

Thus, according to the formula (1)

C_{12}H_{24}O_{6} = 6\times C_{2}H_{4}O

Hence, empirical formula of given molecular formula is C_{2}H_{4}O


4 0
3 years ago
A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vine
QveST [7]

Answer:

0.6743 M

Explanation:

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

First we <u>calculate how many NaOH moles reacted</u>, using the <em>definition of molarity</em>:

  • Molarity = moles / volume
  • moles = Molarity * volume
  • 0.4293 M * 39.27 mL = 16.86 mmol NaOH

<em>One NaOH moles reacts with one acetic acid mole</em>, so <u>the vinegar sample contains 16.86 mmoles of acetic acid as well</u>.

Finally we <u>calculate the concentration (molarity) of acetic acid</u>:

  • 16.86 mmol HC₂H₃O₂ / 25.00 mL = 0.6743 M
4 0
3 years ago
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