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Zigmanuir [339]
3 years ago
15

Assume that an intercontinental ballistic missile goes from rest to a suborbital speed of 6.50 km/s in 60.0 s (the actual speed

and time are classified). What is its average acceleration in m/s2 and in multiples of g (9.80 m/s2)?
Physics
1 answer:
olasank [31]3 years ago
4 0

Answer:

Average acceleration is (11.05)g\ m/s^2

Explanation:

It is given that,

Initial velocity, u = 0

Final velocity, v = 6.5 km/s = 6500 m/s

Time taken, t = 60 s

Acceleration, a=\dfrac{v-u}{t}

a=\dfrac{v}{t}  

a=\dfrac{6500\ m/s}{60}  

a=108.33\ m/s^2

Since, g=9.8\ m/s^2

So, a=(11.05)g\ m/s^2

So, the angular acceleration of the missile is (11.05)g\ m/s^2. Hence, this is the required solution.

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zheka24 [161]

answer is the color white

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A sphere has surface area 1.25 m2, emissivity 1.0, and temperature 100.0°C. What is the rate at which it radiates heat into empt
Yuri [45]
The total power emitted by an object via radiation is:
P=A\epsilon \sigma T^4
where:
A is the surface of the object (in our problem, A=1.25 m^2
\epsilon is the emissivity of the object (in our problem, \epsilon=1)
\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4) is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is T=100^{\circ} C=373 K

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6 0
3 years ago
Unpolarized light with an average intensity of 845 W/m2 moves along the x-axis when it enters a Polarizer A with a vertical tran
horsena [70]

Answer:

θ = 36.2º

Explanation:

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         I = I₀ cos² tea

The non-polarized light between the first polarized of this leaves half the intensity, with vertical polarization

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In this case, the incident light in the second polarizer has an intensity of I₁ = 422.5 W / m² and the light that passes through the polarizer has a value of

I = 275 W / m ²

      Cos² θ = I / I₁

      Cos θ = √ I / I₁

      Cos θ = √ (275 / 422.5)

     Cos θ = 0.80678

     θ = cos⁻¹ 0.80678

     θ = 36.2º

This is the angle between the two polarizers

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Answer:

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