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bagirrra123 [75]
3 years ago
14

Suppose a miracle car has a 100% efficient engine and burns fuel having an energy content of 40 MJ/L. If the air resistance and

overall frictional forces on this car traveling at highway speeds is 1000 N, what is the overall limit in distance per liter driven on the highway?
Physics
1 answer:
Stolb23 [73]3 years ago
3 0

Answer:

Distance traveled in 1 liter = 40 km

Explanation:

Distance traveled = Energy / Opposing force = 40 x 10^6 J / 1000 N = 40000 m or 40 km

So, the car will moves to a distance of 40 km per liter under the opposing force of 1000 N…

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Cuestionario:
Sati [7]

Explanation:

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3 0
3 years ago
A mass m1=1.5 kg rests on a 30 degree ramp with a coefficient of kinetic friction = 0.40. Mass m1 is tied to another mass m with
soldier1979 [14.2K]

Answer:

m = 2.31 Kg

Explanation:

given,

m₁ is the mass rest on the inclined plane = 1.5 Kg

inclination of plane = 30°

Kinetic friction = μ = 0.4

acceleration of the body = 2.68 m/s²

mass m is hanging  = ?

using equation to solve

T - m₁g sin θ - μ m₁g cos θ = m₁ a

on the block on inclined plane there will be acting tension T on the string,

mg sin θ will be the force acting opposite to the tension on the string and a frictional force will be acting which will oppose moment which will be equal to  μ m₁g cos θ

T = m₁(g sin θ +  μ g cos θ + a )

T = 1.5 (9.8 x sin 30° +  0.4 x 9.8 x cos 30°+ 2.68 )

T = 16.46 N

now, forces on the other side of pulley

m g - T = m a

m (g - a ) = T

m = \dfrac{16.46}{9.8-2.68}

m = 2.31 Kg

6 0
3 years ago
An electron with a charge value of 1.6x10^-19 C is in the presence of an electric field of 300 N/C when located between a pair o
Blababa [14]

(1.6 x 10⁻¹⁹ C) x (300 N/C) = <em>4.8 x 10⁻¹⁷ Newton</em>

<em></em>

6 0
4 years ago
Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. what is the truck’s velocity?
klasskru [66]
The momentum of an object is the product between the mass m of the object and its velocity:
p=mv
The truck in our problem has momentum equal to
p=40120 kg m/s 
and a mass of
m=1180 kg
so, if we re-arrange the previous formula, we can use these data to find the velocity of the truck:
v= \frac{p}{m}= \frac{40120 kg m/s}{1180 kg}=34 m/s
5 0
3 years ago
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If a runner exerts 350 J of work to make 125 W of power, then how long did it take the runner to do the work?
PilotLPTM [1.2K]
225 is the correct answer
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3 years ago
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