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slava [35]
2 years ago
11

Your friend is wearing a red coat. When white light hits the coat, some light is reflected, and some is absorbed.

Physics
1 answer:
Vilka [71]2 years ago
4 0

Answer:

Orange , yellow, green and blue

red coat absorbs all colors of visible light except red, so red light

is the only light left to bounce off of the coat toward our eyes.

You might be interested in
A solenoid has a length , a radius , and turns. The solenoid has a net resistance . A circular loop with radius is placed around
geniusboy [140]

This question is incomplete, the complete question is;

A solenoid has a length 11.34 cm , a radius 1.85 cm , and 1627 turns. The solenoid has a net resistance of 144.9 Ω . A circular loop with radius of 3.77 cm is placed around the solenoid, such that it lies in a plane whose normal is aligned with the solenoid axis, and the center of the outer loop lies on the solenoid axis. The outer loop has a resistance of 1651.6 Ω. At a time of 0 s , the solenoid is connected to a battery that supplies a potential 34.95 V. At a time 2.58 μs , what current flows through the outer loop?

Answer:

the current flows through the outer loop is 1.3 × 10⁻⁵ A

Explanation:

Given the data in the question;

Length l = 11.34 cm = 0.1134 m

radius a = 1.85 cm = 0.0185 m

turns N = 1627

Net resistance R_{sol = 144.9 Ω

radius b = 3.77 cm = 0.0377 m

R_o = 1651.6 Ω

ε = 34.95 V

t = 2.58 μs = 2.58 × 10⁻⁶ s

Now, Inductance; L = μ₀N²πa² / l

so

L = [ ( 4π × 10⁻⁷ ) × ( 1627 )² × π( 0.0185 )² ] / 0.1134

L = 0.003576665 / 0.1134

L = 0.03154

Now,

ε = d∅/dt = \frac{d}{dt}( BA ) =  \frac{d}{dt}[ (μ₀In)πa² ]

so

ε = μ₀n \frac{dI}{dt}( πa² )

ε = [ μ₀Nπa² / l ] \frac{dI}{dt}

ε = [ μ₀Nπa² / l ] [ (ε/L)e^( -t/R_{sol) ]

I = ε/R_o = [ μ₀Nπa² / R_ol ] [ (ε/L)e^( -t/R_{sol) ]

so we substitute in our values;

I = [ (( 4π × 10⁻⁷ ) × 1627 × π(0.0185)²) / (1651.6 ×0.1134) ] [ ( 34.95 / 0.03154)e^( -2.58 × 10⁻⁶ / 144.9 ) ]

I = [ 2.198319 × 10⁻⁶ / 187.29144 ] [ 1108.116677 × e^( -1.7805 × 10⁻⁸ )

I = [ 1.17374 × 10⁻⁸ ] × [ 1108.116677 × 0.99999998 ]

I = [ 1.17374 × 10⁻⁸ ] × [ 1108.11665 ]

I = 1.3 × 10⁻⁵ A

Therefore, the current flows through the outer loop is 1.3 × 10⁻⁵ A

7 0
2 years ago
What do neutrons and electrons have in common?
Sergeu [11.5K]
Both make up an atom, along with protons =)
I hope I helped! ^-^
7 0
3 years ago
Read 2 more answers
A device known as an optical resonator is used in lasers. An optical resonator consists of an arrangement of mirrors that reflec
polet [3.4K]

Answer:

A. The resonator behaves as a wave guide (a hollow pipe used as a transmission line). The characteristics of the pipe depend on the type of the wave to be transmitted.

4 0
2 years ago
What is the line that joins northen and southren hemisphere of the earth is called a
svp [43]

The line is called equator.

5 0
3 years ago
A 45.2-kg person is on a barrel ride at an amusement park. She stands on a platform with her back to the barrel wall. The 3.74-m
elena-14-01-66 [18.8K]

Answer:

  • <u><em>1,230N</em></u>

Explanation:

<u>1. Name of the variables:</u>

   f:frequency\\\\ \omega:angular\text{ }speed\\\\ a_c:centripetal\text{ }acceleration\\\\ F_c:centripetal\text{ }force\\ \\ m:mass\\ \\ d:diameter\\ \\ r:radius\\ \\ g:gravitational\text{ }acceleration

<u>2. Formulae:</u>

         f=\dfrac{number\text{ }of\text{ }revolutions}{time}

          \omega=2\pi f

          a_c=\omega^2 r

           F_c=m\times a_c

<u>3. Solution (calculations)</u>

       f=\dfrac{1}{1.65s}=0.\overline{60}s^{-1}

       \omega=2\pi\times0.\overline{60}\approx 3.808rad/s

      a_c=(3.808rad/s)^2\times (3.74/2m)=27.12m/s^2

      F_c=45.2kg\times27.12m/s^2=1,225.67N\approx 1,230N

3 0
3 years ago
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