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REY [17]
3 years ago
13

Prepare a 1.00 L of M solution of sodium carbonate . Determine the amount of sodium carbonate needed incorrect significant figur

es.
A)21g
B) 26.g
C)332g
D ) 424g
Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:b

Explanation:

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Answer:

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Explanation:

Molarity of a solution = number of moles (n) ÷ volume (V)

Molar mass of Mg(NO3)2 = 24 + (14 + 16(3)}2

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Using the formula, mole = mass/molar mass, to convert mass of Mg(NO3)2 to mole

mole = 14g ÷ 148g/mol

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Molarity = 0.095mol ÷ 0.75L

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