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REY [17]
3 years ago
13

Prepare a 1.00 L of M solution of sodium carbonate . Determine the amount of sodium carbonate needed incorrect significant figur

es.
A)21g
B) 26.g
C)332g
D ) 424g
Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
4 0

Answer:b

Explanation:

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C12H22O11 + 11 H2SO4 12 C + 11 H2SO4 + 11 H2O
Vladimir [108]

Answer:

B: The sulfuric acid is not consumed or react with the reactant.

4 0
2 years ago
How many molecules are in 189.5 grams of no2?
xz_007 [3.2K]
<span>NO2 weighs 46.005 grams per mol. There are 6.02x10^23 molecules in a mol. In the given sample of 189.5 grams, there are 4.12 mols. This means that there are 2.48x10^24 molecules of NO2 in the given sample.</span>
5 0
2 years ago
Pls helpits rlly hard
victus00 [196]

Answer:

5: 0.16

6: 50

Explanation:

Question 5:

We can use the equation density = mass/ volume.

We already have the mass (12g), but now we need to find the volume of the cylinder.

The equation for this is πr²h

So we know the radius is 2 and the height is 6.

π x (2)² x 6 = 24π = 75.398cm³

Now we can use the density equation above:

12/75.398 = 0.1592g/cm³ = 0.16g/cm³.

Question 6:

This time, we have to rearrange the equation density = mass/ volume to find the mass.

We know mass = density x volume.

From the question, the density is 2.5g/mL and the volume is 20mL.

Following the equation above, we do 2.5 x 20 to get 50g.

5 0
2 years ago
I need help! how many moles are in 3.4*10^-7 grams of silicon dioxide, SiO2. I got 2.0^17 but I think it's wrong :(
blondinia [14]
Molar mass SiO2 = 28 + 32 = 60 

<span>so moles sand = 3.4 x 10-7 / 60</span>
8 0
3 years ago
The inhibition caused by the final end product of a reaction is called
Troyanec [42]

Answer:

Non competitive inhibition

Explanation:

Hello,

During enzymatic catalysis, the active sites could be occupied by the very same products' molecules turning out into an inhibition (the reaction starts to slow down since to active places are available for the reagents to react). Nonetheless this inhibition is not competitive as long as the product does not react due to the active sites it is occupying.

Best regards.

5 0
2 years ago
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