How many atoms are in 1.50 moles of fluorine gas?

Chemistry

2 answers:

bogdanovich [222]3 years ago

8 0

Answer: The number of atoms in given amount of fluorine gas are $1.807\times 10^{24}$

Explanation:

We are given:

Moles of fluorine gas $(F_2)$ = 1.50 moles

1 mole of fluorine gas contains 2 moles of fluorine atoms

According to mole concept:

1 mole of a substance contains $6.022\times 10^{23}$ number of particles

So, 1.50 moles of fluorine gas will contain $(2\times 1.5\times 6.022\times 10^{23})=1.807\times 10^{24}$ number of atoms.

Hence, the number of atoms in given amount of fluorine gas are $1.807\times 10^{24}$

morpeh [17]3 years ago

4 0

Fluorine gas is a diatomic molecule (two bonded atoms).

So multiply the moles by two and then by Avogadro's number:

(2)(1.50 mol)(6.02x10^23 atoms/mol) = 1.81x10^24 atoms

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5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H

cricket20 [7]

We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572. That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

7 0

3 years ago

An atom with atomic number of 6 would have how many protons?

aalyn [17]

Answer:

Explanation:

Any atom with the atomic number 6 is carbon and has 6 protons

4 0

3 years ago

Read 2 more answers

If 185 mg of acetaminophen were obtained from a tablet containing 350 mg of acetamino- phen, what would be the weight percentage

Alex73 [517]

Percentage recovery gives us an idea of the amount of pure substance recovered after the chemical reaction. Percentage recovery can be more than 100 % or less than 100 %. Usually, in any experiment performed the weight percentage recovery will be less than 100. Percent recovery values greater than 100 show that the recovered compound is contaminated.

Amount of acetaminophen initially taken = 350 mg

Amount of acetaminophen obtained after recovery =185 mg

$Weight percentage recovery =\frac{mass recovered}{mass originally taken}*100$