<span>We can use the heat
equation,
Q = mcΔT </span>
Where Q is the amount of energy transferred (J), m is
the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature
difference (°C).
Let's say
heat gained by 100.10 g of water at 10°C = Q₁
heat lost from 100.0 g of water at 60 °C = Q₂
Final temperature of the mixture = T
<span> Since, there is no heat is lost to the surroundings,
Q</span>
₁ = Q₂ mc(T - 10) = mc(60 - T)
Since, m is same for both sides (100.0 g) and c is a constant for the water, we can cut off m and c from both sides. Then,
(T - 10) =(60 - T)
2T = 60 + 10
2T = 70
T = 35 °C
Hence, final temperature of water is T = 35 °C.
The molarity of the solution will be higher.
Explanation:
Standarization is a process in which the molarity of the solution is made to be known. The concentration determined is exact by this process.
To standarize the solution of NaOH, first the acid used for titration is taken in a flask say 10 ml, indicator and water (in this case 50 ml). Then biuret is filled with NaOH of known molarity and initial volume is noted.
The air bubble not taken notice of in this case will lower the volume as molarity is inversely proportional to volume. When volume decreases molarity increases and vice-versa.
Formula used is
molarity =
The bubble will be formed with minimum volume thus volume is also lowered.
Answer:
8.625 grams of a 150 g sample of Thorium-234 would be left after 120.5 days
Explanation:
The nuclear half life represents the time taken for the initial amount of sample to reduce into half of its mass.
We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.
Initial amount of Thorium-234 available as per the question is 150 grams
So now we start with 150 grams of Thorium-234
So after 120.5 days the amount of sample that remains is 8.625g
In simpler way , we can use the below formula to find the sample left
Where
is the initial sample amount
n = the number of half-lives that pass in a given period of time.
Answer:
The amount of molecules → 6.02×10²³
Explanation:
Avogadro Number (NA) is the amount of particles that are contained in 1 mol of anything.
It does not matter the mass of compounds, or molecules, 1 mol has 6.02×10²³ particles, the same number for every compound.
1 mol of H₂O that weighs 18 grams has 6.02×10²³ molecules
1 mol of sucrose, that weighs 342 g has 6.02×10²³ molecules
Generally, the NA is the number of atoms in 12 grams of the carbon-12 isotope.
Answer:the cation can't be drived from an acid
Explanation:
Example
HCL+MgOH2=MgCl2+H2O
The cation in the salt magnesium chloride is magnesium which is derived from the base and the anion chlorine from the acid hydrochloric acid. The same is true in water.
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