So so false.
Force is not a form of energy.
P = Momentum
M = Mass
t = time
v = velocity (speed)
J= Impulse
1.)
F = 100N
t = 5s
Change in momentum(P) = Ft
I see that this is not one of your equations but your equations do not work with this problem.
P = Ft
P = (100)(5)
P = 500 Ns
2.)
See if you can get this one by yourself from what I did on the last problem.
3.)
P = 25 kgm/s
M = 2.0 kg
So, you are looking for velocity (speed). Look for the equation that has momentum, mass and velocity.
Use the equation P = mv
25 = 2(v)
25 = 2v
25/ 2 = 2v/2
12.5 m/s = v
4.) Do the same for number 4.
P = 12 kgm/s
M = 1kg
P = mv
12 = 1v
12/1 = 1v/1
12 m/s = v
6.)
P = 100 kgm/s
V= 7.0m/s
P= mv
100 = m7.0
100/7 = 7.0m/7
14.28 kg = m
Try page 2 by yourself and message me or comment if you need more help. Just identify the variable you have and what you need to find and put them in an equation that fits. You can do this!!!!
Answer:
The potential at a distance of 0.9 m is 266.67 V.
Explanation:
Charge = Q
Potential is 400 V at a distance 0.6 m .
Let the potential is V at a distance 0.9 m.
Use the formula of potential.
Answer:
(a) Fₓ = 0 N
= 9.08 N
(b)
(a) Fₓ = 0 N
<u></u> = 9.08 N
(c) = 0 N
Fₓ = 9.08 N
Explanation:
The magnitude of the force will remain the same in each case, which is given as follows:
F = ma (Newton's Second Law)
where,
F = force = ?
m = mass = 4.54 kg
a = acceleration = 2 m/s²
Therefore,
F = (4.54 kg)(2 m/s²)
F = 9.08 N
Now, we come to each scenario:
(a)
Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:
<u>Fₓ = 0 N</u>
For upward direction the force will be positive:
<u></u><u> = 9.08 N</u>
<u></u>
(b)
Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:
<u>Fₓ = 0 N</u>
For upward direction the force will be negative:
<u></u><u> = - 9.08 N</u>
<u></u>
(c)
Since the motion is in the horizontal direction. Therefore the magnitude of the force in y-direction will be zero:
<u></u><u> = 0 N</u>
<u>Fₓ = 9.08 N</u>
The results of the experiments should be similar.