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fiasKO [112]
2 years ago
8

Please help me! I really don't understand physics. (Please explain how you got the answers also) Thank you!

Physics
1 answer:
pickupchik [31]2 years ago
3 0
P = Momentum
M = Mass
t = time
v = velocity (speed)
J= Impulse

1.)
F = 100N
t = 5s

Change in momentum(P) = Ft

I see that this is not one of your equations but your equations do not work with this problem.

P = Ft
P = (100)(5)
P = 500 Ns

2.)
See if you can get this one by yourself from what I did on the last problem.


3.)
P = 25 kgm/s
M = 2.0 kg

So, you are looking for velocity (speed). Look for the equation that has momentum, mass and velocity.

Use the equation P = mv

25 = 2(v)
25 = 2v
25/ 2 = 2v/2
12.5 m/s = v

4.) Do the same for number 4.
P = 12 kgm/s
M = 1kg

P = mv
12 = 1v
12/1 = 1v/1
12 m/s = v

6.)
P = 100 kgm/s
V= 7.0m/s

P= mv
100 = m7.0
100/7 = 7.0m/7
14.28 kg = m

Try page 2 by yourself and message me or comment if you need more help. Just identify the variable you have and what you need to find and put them in an equation that fits. You can do this!!!!


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Sam drives her scooter 7 kilometres north. She stops for lunch and then drives
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Answer:

1. Distance travelled = 12 km.

2. Displacement = 8.6 km

Explanation:

From the question given above, the following data were obtained:

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance =?

Displacement =?

1. Determination of the distance travelled.

Distance 1 (d₁) = 7 km

Distance 2 (d₂) = 5 km

Total distance (dₜ) =?

dₜ = d₁ + d₂

dₜ = 7 + 5

dₜ = 12 km

2. Determination of the displacement.

In the attached photo, R is the displacement.

We can obtain the value of R by using the pythagoras theory as illustrated below:

R² = 7² + 5²

R² = 49 + 25

R² = 74

Take the square root of both side

R = √74

R = 8.6 km

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3 0
2 years ago
The speed that a tsunami can travel is modeled by the equation , where s is the speed in kilometers per hour and d is the averag
CaHeK987 [17]

The speed of tsunami is a.0.32 km. 

Steps involved  :

The equation s = 356d models the maximum speed that a tsunami can move at. It reads as follows: s = 200 km/h d =?

Let's now change s to s in the equation to determine d: s = 356√d 200 = 356√d √d = 200 ÷ 356 √d = 0.562 Let's square the equation now by squaring both sides: (√d)² = (0.562) ² d = (0.562)² = 0.316 ≈ 0.32

As a result, 0.32 km is roughly the depth (d) of water for a tsunami moving at 200 km/h.

To learn more about tsunami refer : brainly.com/question/11687903

#SPJ4

6 0
1 year ago
a class of seventh grade students conducted various scientific investigations throughout the year. which statement is the best e
MArishka [77]

Answer:

c

Explanation:it is

5 0
3 years ago
If the final speed of an object as is strikes the ground is 77 m/s and it was in the air for 6.5 seconds. What was the initial d
azamat

Answer:

The answer to your question is: 13.2 m/s

Explanation:

final speed (fs) = 77 m/s

t = 6.5 s

gravity (g) = 9.81 m/s2

initial speed (is) = ?

Formula

fs = is + gt     from this equation we clear "is" = fs - gt

Substitution                         is = 77 - (9,81)(6.5)

Process                               is = 77 - 63.8

                                            is = 13.2 m/s

8 0
2 years ago
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