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fiasKO [112]
3 years ago
8

Please help me! I really don't understand physics. (Please explain how you got the answers also) Thank you!

Physics
1 answer:
pickupchik [31]3 years ago
3 0
P = Momentum
M = Mass
t = time
v = velocity (speed)
J= Impulse

1.)
F = 100N
t = 5s

Change in momentum(P) = Ft

I see that this is not one of your equations but your equations do not work with this problem.

P = Ft
P = (100)(5)
P = 500 Ns

2.)
See if you can get this one by yourself from what I did on the last problem.


3.)
P = 25 kgm/s
M = 2.0 kg

So, you are looking for velocity (speed). Look for the equation that has momentum, mass and velocity.

Use the equation P = mv

25 = 2(v)
25 = 2v
25/ 2 = 2v/2
12.5 m/s = v

4.) Do the same for number 4.
P = 12 kgm/s
M = 1kg

P = mv
12 = 1v
12/1 = 1v/1
12 m/s = v

6.)
P = 100 kgm/s
V= 7.0m/s

P= mv
100 = m7.0
100/7 = 7.0m/7
14.28 kg = m

Try page 2 by yourself and message me or comment if you need more help. Just identify the variable you have and what you need to find and put them in an equation that fits. You can do this!!!!


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Explanation:

hope this helps!

5 0
3 years ago
You hear a sound with a frequency of 256 Hz. The amplitude of the sound increases and decreases periodically: it takes 2 seconds
german

To solve this problem it is necessary to take into account the concepts related to frequency and period, and how they are related to each other.

The relationship that defines both agreements is given by the equation,

f_{beat}=\frac{1}{T}

Then the frequency for the previous period given (2sec) is

f_{beat}=\frac{1}{2}

f_{beat} = 0.5Hz

The beat frequency of two frequencies is equal to the difference between the two frequencies, then

f_{beat} = |f_1-f_2|\\f_{beat} = |256Hz-2Hz|\\f_{beat} = 254Hz

<em>Hence option A is incorrect.</em>

We can do this process for 254Hz as f_1 and 258 Hz for f_2 , then

f_{beat} =|254Hz-258Hz|

f_{beat} = 4Hz

<em>Hence option B is incorrect. </em>

We can also do this process for 255Hz as  f_1 and 257 Hz for f_2 , then

f_{beat} =|255Hz-257Hz|

f_{beat} = 2Hz

<em>Hence option C is incorrect. </em>

We can also do this process for 255.5Hz as f_1 and 256.5 Hz for f_2, then

f_{beat} =|255.5Hz-256.5Hz|\\f_{beat} = 1Hz

<em>Hence option D is incorrect. </em>

We can also do this process for 255.75Hz as f_1 and 256.25 Hz for f_2, then

f_{beat} =|255.75Hz-256.25Hz|\\f_{beat} = 0.5Hz

<em>Hence option E is incorrect. </em>

Therefore the sum of the frequencies in the sound wave would be 256.25Hz and 255.75Hz

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3 years ago
Why is there a wet climate on the windward side of a tall mountain and a dry climate on the leeward side?
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Answer:

23.8 m

Explanation:

The distance travelled by the zebra can be calculated by using the equation:

d=ut+\frac{1}{2}at^2

where

u is the initial velocity

t is the time

a is the acceleration

For this zebra,

u = 0 since it starts from rest

a=1.9 m/s^2 is the acceleration

Substituting t = 5 s, we find the distance travelled by the zebra:

d=0+\frac{1}{2}(1.9)(5)^2=23.8 m

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Frequency and Wavelength

<u>Explanation:</u>

The speed of a wave changes based on frequency and wavelength. Wavelength is the distance between two corresponding points on adjacent waves. Wave frequency is the number of waves that pass a fixed point in a given amount of time. The wave speed depends upon the medium through which the wave is moving. Only an alteration in the properties of the medium will cause a change in the speed.

Speed, frequency and wavelength is related as:

speed  = frequency X wavelength

Increasing the wavelength of a wave doesn’t change its speed. That’s because when wavelength increases, wave frequency decreases. As a result, the product of wavelength and wave frequency is still the same speed.

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