Answer:
The density is 
Explanation:
From the question we are told that
The weight in air is 
The weight in water is 
The weight in a unknown liquid is 
Now according to Archimedes principle the weight of the object in water is mathematically represented as

Where
is he mass of the water displaced
substituting value


Now according to Archimedes principle the weight of the object in unknown is mathematically represented as

Where
is he mass of the unknown liquid displaced
substituting value


dividing equation 2 by equation 1


=> 
Now since the volume of water and liquid displaced are the same then

This because

So if volume is constant
mass = constant * density
Where
is the density of the liquid
and
is the density of water which is a constant with a value 
So


Answer:
28.79%
Explanation:
Given
Design Speed, V = 120km/h = 33.33m/s
Radius, R = 300m
Side Friction, Fs = 0.09
Gravitational Constant = 9.8m/s²
Using the following formula, we'll solve the required rate of superelevation.
e + Fs = V²/gR where e = rate
e = V²/gR - Fs
e = (33.33)²/(9.8 * 300) - 0.09
e = 0.287853367346938
e = 28.79%
Hence, the required rate of superelevation for the curve is calculated as 28.79%
To solve the problem it is necessary to identify the equation in the manner given above.
This equation corresponds to the displacement of a body under the principle of simple harmonic movement.
Where,

PART A) Our equation corresponds to

Therefore the value of omega is equivalent to that of

From the definition we know that the period as a function of angular velocity is equivalent to



This same point is the equivalent of the maximum point of the speed that the body can reach, since the internal expression of the
Is equivalent to . So the maximum speed that the body can reach is,



Therefore the maximum felocity will be 5ft / s
PART B) The period of graph is the time taken to reach from one maximum point to next point maximum point, then


Answer
Given,
Periscope uses 45-45-90 prisms with total internal reflection adjacent to 45°.
refractive index of water, n_a = 1.33
refractive index of glass, n_g = 1.52
When the light enters the water, water will act as a lens and when we see the object from the periscope the object shown is farther than the usual distance.
Work done against gravity to climb upwards is always stored in the form of gravitational potential energy
so we can say

here h = vertical height raised
so here we know that

here we have

now from above equation


so work done will be given by above value