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UkoKoshka [18]
3 years ago
15

In a step-down transformer, which side has more wire loops?

Chemistry
2 answers:
Over [174]3 years ago
8 0
B because the secondary side has more cells
Marat540 [252]3 years ago
7 0
B. The Secondary side of the step down transformer.
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How many miles of glucose are in 19.1 g of glucose
geniusboy [140]

Answer:

did you mean moles? If so, answer is down below.

Explanation:

there are 0.106 moles of glucose in 19.1 g of glucose.

7 0
2 years ago
Leopard seals are animals adapted to survive in the freezing conditions of Antarctica. Individual leopard seals vary in their di
andreev551 [17]

Answer:

B. Thicker layer of blubber

Explanation:

For the leopard seals to survives this harsh environment, it must have a thicker layer of blubber

Blubber is a thick layer of fat. It is called the adipose tissues and found in most marine organisms.

  • This layer helps in insulating the body against heat loss.
  • By so doing, the animal is able to conserve internal heat.
  • They have low thermal conductivity and do not easily lose heat or gain heat as such.
6 0
2 years ago
Urgent!! A chemist measured 5.2 g copper(II) bromide tetrahydrate (CuBr2•4(H2O)). How many moles were measured out? Answer in un
bezimeni [28]
  The  moles  which  were   measured  out  is  calculated  using  the  following  formula

moles  =  mass/molar   mass

molar mass  of  CuBr2.4H20  =   63.5  Cu + (  2  x79.9)  br  + ( 18  x4_)  h20  =  295.3  g/mol

moles  is therefore=  5.2 g/  295.3 g/mol=  0.0176 moles
4 0
2 years ago
Read 2 more answers
How many molecules of CaCl2 are equivalent to 75.9 g CaCl2
sergij07 [2.7K]
First, you need to find:
One mole of CaCl_{2} is equivalent to how many grams?

Well, for this you have to look up the periodic table. According to the periodic table:
The atomic mass of Calcium Ca = 40.078 g (See in group 2)
The atomic mass of <span>Chlorine Cl = 35.45 g (See in group 17)
</span>
As there are two atoms of Chlorine present in CaCl_{2}, therefore, the atomic mass of CaCl_{2} would be:

Atomic mass of CaCl_{2}  = Atomic mass of Ca + 2 * Atomic mass of Cl

Atomic mass of CaCl_{2} = 40.078 + 2 * 35.45 = 110.978 g

Now,

110.978 g of CaCl_{2} = 1 mole.
75.9 g of CaCl_{2} = \frac{75.9}{110.978} moles = 0.6839 moles.

Hence,
The total number of moles in 75.9g of CaCl_{2} = 0.6839 moles

According to <span>Avogadro's number,
1 mole = 1 * </span>6.022 * 10^{23} molecules
0.6839 moles = 0.6839 * 6.022 * 10^{23} molecules = 4.118*10^{23} molecules

Ans: Number of molecules in 75.9g of  CaCl_{2} =  4.118*10^{23} molecules

-i


3 0
2 years ago
Read 2 more answers
Calculate the area of an applied force of 300 N and a pressure of 35 Pa? (the answer needs to be accurate with 2 decimal places!
andreyandreev [35.5K]

Answer:

Explanation: 1Pa 1 N/m^2. p = F/A and A = F/p = 300N /35 Pa = 8.57 m^2

4 0
2 years ago
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