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Lubov Fominskaja [6]
3 years ago
13

A one or two letter abbreviation for a chemical element. True or false

Chemistry
1 answer:
Feliz [49]3 years ago
3 0

Answer:

True

Explanation:

All the chemical elements have their abbreviations as one or two letters

The first letter in the abbreviation is a capital letter and the second letter is always a small letter

Majority of abbreviations are based on their english names

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Answer this question fast please!
MrRissso [65]

Answer:

A is a physical change, no atoms are being lost its still in it original form

B is a chemical change, it is losing atoms and changing into a new substance

Explanation:

5 0
3 years ago
Calculate the molecular mass of Co(NO3)2<br>with steps please
Nana76 [90]

Answer:

182.933~ \text{g mol}^{-1}

Explanation:

\text{Atomic mass of cobalt(Co)} = 58.933~u\\\\\text{Atomic mass of nitrogen(N)}= 14~u\\\\\text{Atomic mass of oxygen(O)}=16~u\\\\\text{Molar mass of}~ \text{Co}\left(\text{NO}_3} \right)_2 = 58.933 + 2(14 +16 \times 3)~ \text{g mol}^{-1}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=(58.933 + 124)~ \text{g mol}^{-1}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=182.94~ \text{g mol}^{-1}

4 0
2 years ago
What is effective nuclear charge?
Amiraneli [1.4K]

Answer:

The effective nuclear charge (often symbolized as Zeff or Z*) is the net positive charge experienced by an electron in a multi-electron atom. The term “effective” is used because the shielding effect of negatively charged electrons prevents higher orbital electrons from experiencing the full nuclear charge.

Explanation:

6 0
3 years ago
What types of hydrocarbons are usually liquid at room temperature?
marishachu [46]

<span>These hydrocarbons are many and this depends on the phase diagram of the substance. In a phase diagram, the phase can be determined by looking at a certain temperature and pressure. For this case, at a temperature of 20 degrees Celsius and at 1 atmosphere.</span>

8 0
3 years ago
¿Cuál es el % m/m de una disolución en que hay disueltos 22 g de soluto en 44 g de disolvente?
Archy [21]

The question is as follows: What is the% m / m of a solution in which 22 g of solute are dissolved in 44 g of solvent?

Answer: The% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.

Explanation:

Given: Mass of solute = 22 g

Mass of solvent = 44 g

The percentage m/m is calculated using the following formula.

Mass percentage = \frac{mass of solute}{mass of solvent} \times 100

Substitute the values into above formula as follows.

Mass percentage = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{22 g}{44 g} \times 100\\= 50 percent

Thus, we can conclude that the% m/m of a solution in which 22 g of solute are dissolved in 44 g of solvent is 50%.

5 0
3 years ago
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