Calculate the molecular mass of Co(NO3)2with steps please

Chemistry

1 answer:

Nana76 [90]2 years ago

4 0

Answer:

$182.933~ \text{g mol}^{-1}$

Explanation:

$\text{Atomic mass of cobalt(Co)} = 58.933~u\\\\\text{Atomic mass of nitrogen(N)}= 14~u\\\\\text{Atomic mass of oxygen(O)}=16~u\\\\\text{Molar mass of}~ \text{Co}\left(\text{NO}_3} \right)_2 = 58.933 + 2(14 +16 \times 3)~ \text{g mol}^{-1}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=(58.933 + 124)~ \text{g mol}^{-1}\\\\~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~=182.94~ \text{g mol}^{-1}$

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Iron fluoride (FeF2) dissociates according to the following equation:

melomori [17]

Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

$Kps = \frac{[product]^x}{[reagent]^y}$

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of $Fe^{+2}$ is necessary 2 mols of $F^-$ , so if we call "x" the molar concentration of $Fe^2$ , for $F^-$ we will have 2x, so:

$Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L$