<u>Answer:</u> The percent composition of 
in taconite is 37.6 %.
<u>Explanation:</u>
We are given:
Mass of taconite pellets = 1 ton = 907185 g (Conversion factor: 1 ton = 907185 g)
Mass of iron produced = 545 lb = 247212 g (Conversion factor: 1 lb = 453.6 g )
We know that:
Molar mass of iron = 55.85 g/mol
Molar mass of = 231.53 g/mol
1 mole of contains 3 moles of iron atom and 4 moles of oxygen atom
(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of
So, 247212 grams of iron will be produced from = 
of
To calculate the percentage of in taconite, we use the equation:
Mass of taconite = 907185 g
Mass of = 341611.43 g
Putting values in above equation, we get:
Hence, the percent composition of in taconite is 37.6 %.
All are gases so no visible reaction persay, unless in closed quarters and then massive pressure.
A bond is non polar if it is between same atoms and polar if it is between different atoms.
Same atoms are like two dogs of same strength pulling a bone towards towards each other. But when it’s different atoms it’s like a big dog and small dog then the bone is more towards bigger dog. So it’s the same way in bonds.
Bonds are made up of electrons, when the more stronger pulling atom is present than other the electrons are more towards it and as a result we have polar bond. There is development of a kind of a negative pole and a positive pole.
The stronger atom has electrons towards itself so it has a little more negative charge while the other atom has positive charge. This makes bond polar.
So just look for bond between two different atoms, it would be polar.
Look at the pic below to see the answer.
Marked with green is bond between same atoms... one carbon and another carbon so it is not polar and test marked with blue are polar.
Well the answer should have been 10 but since the bonds at 3 and 8 are two of same type we count only one of them.
The answer is 8... well the answer should be 10 otherwise... discuss it with ur teacher
Interphase is not a phase of mitosis.
Answer:
72.53% is the yield of CrCl3
Explanation:
Given
Reaction:
Cr2O3(s) + 3 CCl4(l) → 2 CrCl3(s) + 3 COCl2(aq)
CCl4 is in excess and 17.6g Cr2O3 present
The reaction yields 26.6g of CrCl3
To Find:
% yields of the reaction
Also given
Molar mass of CrCl3 = 158.35g/mol
Molar mass of Cr2O3 = 152.00 g/mol
By the stoichiometry of the reaction
1 mole of Cr2O3 gives 2 moles of CrCl3
0r
1 x1 52 g of Cr2O3 gives 2x 158.35 g of CrCl3
= 1 52 g of Cr2O3 gives 316.70 g of CrCl3
17.6 g of Cr2O3 gives (17.6÷152) × 316.70 g CrCl3
= 36.67 g CrCl3
but actual yield is only 26.6g
so % yield is (26.6 ÷÷ 36.67) × 100
= 72.53% is the yield of CrCl3
