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Savatey [412]
3 years ago
13

which would be better suited for agriculture, the soil of a tropical rain forest or that of a temperate deciduous forest

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0
I think it may be that of a temperate deciduous forest tho im not sure
thank u for letting me answer and god bless have a good life <3
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Question 15 (3.33 points) Solve: What work is done when 3.0 C is moved through an electric potential difference of 1.5 V?
horsena [70]

Answer:

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Explanation:

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4. Two forces act on a 2 kg object as shown. What is the magnitude of the acceleration of the object?
aleksandrvk [35]

The resultant force on the object is

∑ <em>F</em> = 〈0, 8〉 N + 〈6, 0〉 N = 〈6, 8〉 N

which has a magnitude of

<em>F</em> = √((6 N)² + (8 N)²) = √(100 N²) = 10 N

By Newton's second law, the acceleration has magnitude <em>a</em> such that

<em>F</em> = <em>m a</em>

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so the answer is B.

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7. Which phase changes require a gain of energy (heat)?
Keith_Richards [23]

Answer:

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7 0
3 years ago
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What is the unit of k (spring constant) in SI system?
Gre4nikov [31]

Answer:

SI unit of k (spring constant) = N/m

Explanation:

We have expression for force in a spring extended by x m given by

         F = kx

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Taking units on both sides

         Unit of F = Unit of k x Unit of x

          N = Unit of k x m

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SI unit of k (spring constant) = N/m

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If a system has 225 kcal of work done to it, and releases 5.00 × 102 kj of heat into its surroundings, what is the change in int
vovikov84 [41]

We can solve the problem by using the first law of thermodynamics:

\Delta U = Q-W

where

\Delta U is the change in internal energy of the system

Q is the heat absorbed by the system

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In this problem, the work done by the system is

W=-225 kcal=-941.4 kJ

with a negative sign because the work is done by the surrounding on the system, while the heat absorbed is

Q=-5 \cdot 10^2 kJ=-500 kJ

with a negative sign as well because it is released by the system.


Therefore, by using the initial equation, we find

\Delta U=Q-W=-500 kJ+941.4 kJ=441.4 kJ

8 0
3 years ago
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