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Vaselesa [24]
3 years ago
5

When a muscle is working, it _________, or tightens, thus making itself stronger.

Physics
1 answer:
Cloud [144]3 years ago
8 0

Answer: contracts, its a synonym.

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A pilot flies in a straight path for 1 hour 30 minutes. She then makes a course correction, heading 45 degrees to the right of h
mrs_skeptik [129]

Answer:

1199 miles

Explanation:

1 hour 30 minutes = 1 + 30/60 = 1.5 hours

2 hours 15 minutes = 2 + 15/60 = 2.25 hours

The distance she flew in the 1st segment is:

1.5*345 = 517.5 miles

The distance she flew in the 2nd segment is:

2.25 * 345 = 776.25 miles

Since the 2nd segment is 45 degree with respect to the 1st segment, this means that she has flown

776.25 * cos(45) = 549 miles in-line with the 1st segment and

776.25* sin(45) = 549 miles perpendicular to the 1st segment:

So the distance from the end to her starting position is

\sqrt{(517.5 + 549)^2 + 549^2} = 1199 miles

4 0
3 years ago
Two elements in Period 4 that are most similar to Cobalt?
lisabon 2012 [21]
Iron and nickel are the elements most similar to cobalt
5 0
3 years ago
Do it in order. <br> from smallest to largest
Sholpan [36]

Answer:

The earth, The sun, the solar system and the milky way.

7 0
2 years ago
Which object will have greater acceleration? Why?​
dexar [7]

Answer:

Object D

Explanation:

Use Newton's Second Law to determine the acceleration that each object has.

  • F = ma

The force applied in both cases is 50 N, but the mass for object C and object D is different.

Let's start with object C first:

  • F = ma
  • 50 N = 10 kg · a
  • 50 = 10a
  • 5 = a

The acceleration object C undergoes is 5 m/s².  

Now let's calculate object D next:

  • F = ma
  • 50 N = 2 kg * a
  • 50 = 2a
  • 25 = a

The acceleration object D undergoes is 25 m/s².

Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.

7 0
3 years ago
Suppose a car manufacturer tested its cars for front-en4 collisions by hauling them up on a crane and dropping then; from a cert
Brrunno [24]

Answer:

a

Generally from third equation of motion we have that

v^2 =  u^2 + 2a[s_i - s_f]

Here v is the final speed of the car

u is the initial speed of the car which is zero

s_i is the initial position of the car which is certain height H

s_i is the final position of the car which is zero meters (i.e the ground)

a is the acceleration due to gravity which is g

So

v^2 = 0 + 2g[H - 0]

=> v  =  \sqrt{ 2 g H}

b

H  =  9.86 \  m

Explanation:

Generally from third equation of motion we have that

v^2 =  u^2 + 2a[s_i - s_f]

Here v is the final speed of the car

u is the initial speed of the car which is zero

s_i is the initial position of the car which is certain height H

s_i is the final position of the car which is zero meters (i.e the ground)

a is the acceleration due to gravity which is g

So

v^2 = 0 + 2g[H - 0]

=> v  =  \sqrt{ 2 g H}

When v  = 50 \  km/h = \frac{50 *1000}{3600} = 13.9 \  m/s we have that

13.9  =  \sqrt{ 2 g H}

=> H  =  \frac{13.9^2}{2 *  9.8}

=> H  =  9.86 \  m

6 0
3 years ago
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