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2 years ago

How much thermal energy is Generated?

Physics

2 answers:

kogti [31]2 years ago

5 0

Answer:

1000 J of thermal energy is generated.

Explanation:

The attached figure shows the whole scenario. It consists of three types of energies i.e. Gravitational Potential Energy, Kinetic Energy and thermal energy.

We know that the energy of a system remains conserved. In this case, the gravitational potential energy is the sum of kinetic energy and the thermal energy.

GPE = KE +TE

8000 J = 7000 J + TE

TE = 1000 J

So, the thermal energy is 1000 J. Hence, this is the required solution.

Archy [21]2 years ago

4 0

According to me, if you want to find this answer by fair means or foul then you can :P . Answer will be 1000J

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3 years ago

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2 years ago

A worker lifts a 20.0-kg bucket of concrete from the ground up to the top of a 25.0-m tall building. The bucket is initially at

yuradex [85]

Answer:

Minimum work = 5060 J

Explanation:

Given:

Mass of the bucket (m) = 20.0 kg

Initial speed of the bucket (u) = 0 m/s

Final speed of the bucket (v) = 4.0 m/s

Displacement of the bucket (h) = 25.0 m

Let 'W' be the work done by the worker in lifting the bucket.

So, we know from work-energy theorem that, work done by a force is equal to the change in the mechanical energy of the system.

Change in mechanical energy is equal to the sum of change in potential energy and kinetic energy. Therefore,

$\Delta E=\Delta U+\Delta K\\\\\Delta E= mgh+\frac{1}{2}m(v^2-u^2)$

Therefore, the work done by the worker in lifting the bucket is given as:

$W=\Delta E\\\\W=mgh+\frac{1}{2}m(v^2-u^2)$

Now, plug in the values given and solve for 'W'. This gives,

$W=(20\ kg)(9.8\ m/s^2)(25\ m)+\frac{1}{2}(20\ kg)(4^2-0^2)\ m^2/s^2\\\\W=4900\ J +160\ J\\\\W=5060\ J$

Therefore, the minimum work that the worker did in lifting the bucket is 5060 J.

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3 years ago