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Jlenok [28]
3 years ago
5

Please Hurry worth 80 point!They're 3 pages

Physics
1 answer:
olchik [2.2K]3 years ago
5 0

Answer:

the answer is angle of refraction

the angle between a refracted ray and the normal drawn at the point of incidence to the interface at which refraction occurs

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A force of 7.50 N is applied to a spring whose spring constant is .298 N/cm. Find it’s length
gizmo_the_mogwai [7]

Answer:

to find the length just divide 7.50 and . 298

5 0
3 years ago
Phobos's Orbit. Phobos orbits Mars at a distance of 9,380 km from the center of the planet and has a period of 0.3189 days. Assu
Elenna [48]

Answer:

Explanation:

The relation between time period of moon in the orbit around a planet can be given by the following relation .

T² = 4 π² R³ / GM

G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .

Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)²  = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )

M = .06424  x 10²⁵

= 6.4 x 10²³ kg .

4 0
3 years ago
A wave with a greater amplitude will transfer . . . . \
Orlov [11]

Answer:

More energy

Explanation:

The amount of energy carried by a wave is related to the amplitude of the wave itself. In particular, the amount of energy carried by the wave is proportional to the square of the amplitude of the wave:

E \propto A^2

where

E is the energy

A is the amplitude

This means, for instance, that if the amplitude of a wave is doubled, the energy it carries increases by a factor 4.

8 0
3 years ago
A 15 000-N car on a hydraulic lift rests on a cylinder with a piston of radius 0.20 m. If a connecting cylinder with a piston of
victus00 [196]

Answer:

the force applied to the smaller piston is 600 N

Explanation:

Given;

weight of the car, F = 15,000 N

radius of the lager piston, R = 0.2 m

radius of the smaller piston, r = 0.04 m

let the force applied to the smaller piston = f

The pressure applied on both piston is constant;

P = \frac{F}{A} = \frac{f}{a} \\\\\frac{F}{R^2} = \frac{f}{r^2} \\\\f = \frac{F\times r^2}{R^2} = \frac{15,000 \times (0.04)^2}{(0.2)^2} = 600 \ N

Therefore, the force applied to the smaller piston is 600 N

5 0
3 years ago
10. Complete each of the following radioactive decay equations.
alukav5142 [94]

1. Alpha

Number next to Th is 231

(because 231 + 4 = 235)

The other number below the 4 is 2 - helium

(because 90 + 2 = 92)

2. Beta

Missing numbers are zero and one. Same as the one below it.

3. Beta

11 is the number above the C

(because 11 + 0 = 11)

5 is the number next to the B

(because 5 + 1 = 6)

Basically, the missing numbers must balance on both side of the equation; creating the elements you've started of with, meaning if you where to add the right side of the equation up - you should end up with the same protons and mass numbers you began with.

Hope this helps!

6 0
1 year ago
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