Ka is the equilibrium constant for the ionization for a reaction. It is calculated as follows
ka is equal to (H3o ions)(A-) divided by (HA)
2.00x106i s equal to 0.153x0.153 divided by ( HA)
(2.00x106)HA is equal to 0.023409
HA concentration is therefore equal to 0.023409/2.00x106 which is 1.104x10^-4moles/litre
2N2 + 3O2 ---> 2NO + 2NO2
You should do it based on moles and not grams.
1.14 g O = 0.071 moles O
1 g N = 0.071 moles N
So in NO2 you need 2 moles O for each mole of N
1 g N = 0.071 moles, so you need 0.071 x 2 moles of O = 0.0.142 moles O
0.142 moles O x 16 g/mol = 2.27 grams of O. So, you are actually correct because your answer is 2.28 grams. I just prefer to work it out in moles so it makes perfect chemical sense.
Answer:
They all have a hydrogen written separatly towards the beginning of the formula.
Explanation:
If you look at the Arrhenius acid formulas, you can see they all contain a hydrogen (H) at the beginning of them.
Mass number is equal to the sum of number of neutrons (neutral subatomic particle) and number of protons (positively charge particle).
Mass number =
Now, atomic number is same as the number of protons i.e. atomic of nitrogen is 7 . Thus, number of protons is also equal to 7.
Therefore,
Mass number =
= 
Hence, mass number of nitrogen is equal to .
