Question

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Answer 1

Given quadratic equation$x^2+6x+6=0$
Using the usual conventions, 
a=1, b=6, c=6
Apply the quadratic formula,
$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
substitute a,b & c with numerical values,
$x=\frac{-6\pm\sqrt{6^2-4(1)(6)}}{2(1)}$
simplify:
$x=\frac{-6\pm\sqrt{12}}{2}$