(a) The initial speed at which the bottles are launched is 4.27 m/s.
(b) The horizontal displacement at which the bottle land is 1.75 m.
<h3>Initial speed of the bottle</h3>
The initial speed of the bottle is calculated as follows;

where;
- T is time of flight
- u is the initial speed
2usinθ = Tg
u = Tg/(2sinθ)
u = (0.5 x 9.8)/(2 x sin35)
u = 4.27 m/s
<h3>Horizontal displacement of the bottle</h3>
X = u²sin(2θ)/g
X = (4.27² x sin(70))/(9.8)
X = 1.75 m
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Answer:
F - M a force exerted by scales on student
M a = M (9.8 + 4.9) m/s^2 upwards chosen as positive
a = 1.5 g net acceleration of student due to force of scales
W =M g weight of student (actual weight)
Wapp = M 1.5 * g apparent weight (on scales) of student
Explanation:
The gravitational force equation is the following:

Where:
G = Gravitational constant = 
m1 & m2 = the mass of two related objects
r = distance between the two related objects
The problem gives you everything you need to plug into the formula, except for the gravitational constant. Let me know if you need further clarification.
Answer:
C) upward
Explanation:
The problem can be solved by using the right-hand rule.
First of all, we notice at the location of the negatively charged particle (above the wire), the magnetic field produced by the wire points out of the page (because the current is to the right, so by using the right hand, putting the thumb to the right (as the current) and wrapping the other fingers around it, we see that the direction of the field above the wire is out of the page).
Now we can apply the right hand rule to the charged particle:
- index finger: velocity of the particle, to the right
- middle finger: direction of the magnetic field, out of the page
- thumb: direction of the force, downward --> however, the charge is negative, so we must reverse the direction --> upward
Therefore, the direction of the magnetic force is upward.
Answer: conduction :it transfers heat between objects that are in direct contact with eachother