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3 years ago

What does the model below represent?

Physics

2 answers:

serious [3.7K]3 years ago

8 0

Answer:

B. a chemical reaction

Explanation:

2CO + O2 → 2C02

Serjik [45]3 years ago

5 0

Answer:

B. A chemical reaction

it's formed when carbon monoxide react with oxygen and forms carbon dioxide

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At a maximum level of loudness, the power output of a 75-piece orchestra radiated as sound is 72.0 W. What is the intensity of t

FrozenT [24]

Answer:

<em> The intensity would be 0.01432 W/</em> $m^{2}$ <em></em>

Explanation:

The sound intensity is the power that is transmitted by a sound wave per unit area.

Given that

Power output P of the 75-piece orchestra = 72.0 W

The listener's distance r = 20.0 m

The intensity of sound waves (I) can be obtained with the expression below;

I = P/A .............. 1

where P is the power

A is the area, in this case, at the distance r the sound is radiated through a sphere.

A = area of a sphere = 4π $r^{2}$

putting it into equation 1, the intensity would be;

I = P/ 4π $r^{2}$

Substituting our values we have;

I = 72.0 W / 4 π $20^{2}$ $m^{2}$

I = 0.01432 W/ $m^{2}$

Therefore the intensity would be 0.01432 W/ $m^{2}$

3 0

3 years ago

Calcula la densidad del hierro , si 393 g ocupan un volumen de 50 ml

eimsori [14]

Density is mass over volume: d=m/v
d = 393/50 => d = 7.86 g/ml

7 0

3 years ago

Compare the gravitational acceleration on the following objects compared to the Sun using:

arsen [322]

The gravitational acceleration of White dwarf compared to Sun is 13,675.86.

The gravitational acceleration of Neutron star compared to Sun is 6.79 x 10⁻²⁴.

The gravitational acceleration of Star Betelgeuse compared to Sun is 8.5 x 10¹⁰.

<h3>Mass of the planets</h3>

Mass of sun = 2 x 10³⁰ kg

Mass of white dwarf = 2.765 x 10³⁰ kg

Mass of Neutron star = 5.5 x 10¹² kg

Mass of star Betelgeuse = 2.188 x 10³¹ kg

<h3>Radius of the planets</h3>

Radius of sun = 696,340 km

Radius of white dwarf = 7000 km

Radius of Neutron star = 11 km

Radius of star Betelgeuse = 617.1 x 10⁶ km

<h3>Gravitational acceleration of White dwarf compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.765 \times 10^{30}}{2\times 10^{30}} \times [\frac{696,340,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 13,675.86$

<h3>Gravitational acceleration of Neutron star compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{5.5 \times 10^{12}}{2\times 10^{30}} \times [\frac{11,000}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 6.79\times 10^{-24}$

<h3>Gravitational acceleration of Star Betelgeuse compared to Sun</h3>

$\frac{g(star)}{g(sun)} = \frac{M(star)}{M(sun)} \times [\frac{R(sun)}{R(star)} ]^2\\\\\frac{g(star)}{g(sun)} = \frac{2.188 \times 10^{31}}{2\times 10^{30}} \times [\frac{617.1 \times 10^9}{7,000,000} ]^2\\\\\frac{g(star)}{g(sun)} = 8.5\times 10 ^{10}$

Learn more about acceleration due to gravity here: brainly.com/question/88039

3 0

3 years ago

A car’s headlights dissipate 40 W on low beam and 50 W on high beam. Is there more or less resistance in the high-beam filament?

love history [14]

Answer:

The high-beam filament has more resistance than low beam filament.

Explanation:

To determine if the 50 W dissipated by a car’s headlights on high beam, has more or less resistance, formula for power dissipated in the filament is used.

Power = IV

Voltage =IR

∴ Power = I*IR = I²R

where;

I is the current

V is the voltage

R is the resistance

From the equation above, Power dissipated is directly proportional to Resistance.

Hence, the high-beam filament has more resistance than low beam filament.

3 0

3 years ago

Question 12 (10 points)

Leni [432]

Answer:

d jjh hhv g 7655 ijv 77_* uyfgj 3&88 huih

6 0

2 years ago