4 years ago

What did the diver most likely use as a reference point to describe the position of the squid?

Physics

1 answer:

alexira [117]4 years ago

7 0

The surface of the water or himself

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A bullet of mass 0.01 kg is fired in to a sand bas of mass 0.49 kg from a tree. The Sand bag with the bullet embedded in to it s

makvit [3.9K]

Since the bag was at rest, its initial momentum is zero. The velocity of the ball before collision is 500 ms-1.

<h3>Linear momentum</h3>

The term momentum in physics refers the product of mass and velocity. If we know mass of the object and its velocity, then we calculate the momentum.

Momentum before collision for the bullet = 0.01 kg × v

Momentum before collision for the bag = 0

Momentum after collision for the bag and bullet = (0.01 kg + 0.49 kg) 10 = 5 Kgms-1

The velocity of the bullet before collision = 0.01 kg × v + 0 = 5 Kgms-1

v = 5 Kgms-1/0.01 kg

v = 500 ms-1

Learn more about momentum: brainly.com/question/904448

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3 years ago

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A body of mass 500kg moving at a speed of 10m/s reaches the speed of 50m/s in 20s.The force exerted is

Leona [35]

Answer:

answer is 1000 N

formula used-

F= m x (v-u/t)

mark this as brainliest!

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3 years ago

The position of a 55 g oscillating mass is given by x(t)=(2.0cm)cos(10t), where t is in seconds. determine the velocity at t=0.4

NNADVOKAT [17]

The position of the mass is given by (in cm):
$x(t)=2 \cos (10 t)$
The velocity is the derivative of the position:
$v(t) = \frac{dx(t)}{dt} =-10\cdot 2 \sin (10t)=-20 \sin (10t)$
Substituting t=0.40 s, we can find the velocity at this time:
$v(0.40 s)= -20 \sin (10 \cdot 0.4)=15 cm/s=15 \cdot 10^{-2}m/s$

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3 years ago

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3 years ago

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Pepsi [2]

Explanation:

acceleration is weight*gravity