Answer:
You can describe the<u> motion </u>of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its <u> position </u> in relation to another object. The second object acts as a<u> reference</u> point. When an object changes position, you know it has motion. Motion can also be described by finding an object's <u>speed </u>or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called <u>velocity</u>
Explanation:
In the given answer-
<u>Motion</u> is defined as - the change in the movement or position of any object or body.
<u>Position</u> is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.
<u>Reference poin</u>t is a fixed point with regards to which any object or body changes its position. It is also called reference origin.
<u>Speed</u> is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).
<u>Velocity</u> is defined as the rate of speed per unit time. It is a vector quantity (quantity depending upon both magnitude and direction ).
Answer:
a. Wet, soft dough at 85 degrees Fahrenheit
Explanation:
Fermentation is an anaerobic process that transforms starches into simpler substances. The rising of dough is due to fermentation.
According to Harold McGee, 85°F (29°C) is the best temperature for fermenting bread dough. Temperatures below 85°F (29°C) take much longer to ferment, and temperatures higher than that result into unpleasant flavors in the dough.
Wet, soft dough is usually more preferable because it produces a softer bread.
sound travels through a medium in mechanical waves a mechanical wave is a disturbance that moves and transports energy from one place to another through a medium
w = instantaneous angular speed = 1.25 rad/s
r = radius = 4.65 m
α = angular acceleration = 0.745 rad/s²
centripetal acceleration is given as
= rw²
= (4.65 ) (1.25)² = 7.27 m/s²
tangential acceleration is given as
= rα
=4.65 x 0.745 = 3.46 m/s²
angle is given as
= 64.5 deg
We can use constant acceleration equation to solve for the distance.
Formula is:
Vf^2 = Vi^2 + 2ad
where Vf^2 is final velocity squared, Vi^2 is initial velocity squared, a is acceleration (or deceleration) and d is the distance.
we want the car to come to complete stop, that is, Vf^2 be equal to zero.
Therefore, the equation becomes 0 = Vi^2 + 2ad. Solving for d we get:
d = (-(Vi)^2)/2a). We can ignore the minus sign since acceleration is really deceleration.
We know initial velocity (23m/s) and we know acceleration (max= 300 m/s^2). Plugging these in, we get:
d = ((23 m/s)^2)/(2* 300m/s^2) = <span>0.88m </span>
<span>hope that helps</span>
