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sergejj [24]
3 years ago
11

Certain types of organisms such as fireflies and anglerfish can produce light

Chemistry
2 answers:
Nastasia [14]3 years ago
8 0

Answer:

B

Explanation:

sesenic [268]3 years ago
3 0
The answer is B






Explanation
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Write the correct name of the following compounds: <br> A. Sr(NO3)2 <br> B. CuBr2 <br> C. N2O4
nikdorinn [45]
A. Strontium nitrate;
B. Copper (II) bromide; 
C. Dinitrogen tetroxide.
5 0
3 years ago
The smallest atoms can themselves exhibit quantum-mechanical behavior. Calculate the de Broglie wavelength (in picometers) of a
Sunny_sXe [5.5K]

Answer:

810 pm

Explanation:

Step 1: Given and required data

  • Velocity of the atom (v): 490 m/s
  • Mass of a hydrogen atom (m): 1.67 × 10⁻²⁷ kg
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s

Step 2: Calculate the de Broglie wavelength of the hydrogen atom

We will use de Broglie's equation.

λ = h / m × v

λ = 6.63 × 10⁻³⁴ J.s / 1.67 × 10⁻²⁷ kg × 490 m/s = 8.10 × 10⁻¹⁰ m

Step 3: Convert 8.10 × 10⁻¹⁰ m to picometers

We will use the conversion factor 1 m = 10¹² pm.

8.10 × 10⁻¹⁰ m × 10¹² pm/1 m = 810 pm

5 0
3 years ago
You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain
____ [38]

6.9 Sleps 1. (8)(13) = 15 2. 104/15 = 15/15 3. 6.93333333 4. 6.9 Sleps

6 0
3 years ago
Read 2 more answers
It takes 338. kJ/mom to break a carbon-chlorine single bond. Calculate the maximum wavelength of light for which a carbon-chlori
Vesnalui [34]

Answer: The maximum wavelength of light for which a carbon-chlorine Single bond could be broken by absorbing a single photon is 354 nm

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

E=\frac{Nhc}{\lambda}

where,

E = energy of the light  = 338kJ=338000J    (1kJ=1000J)

N= avogadro's number

h = Planck's constant

c = speed of light

\lambda = wavelength of light

338\times 1000J=\frac{6.023\times 10^{23}\times 6.6\times 10^{-34}\times 3\times 10^{8}}{\lambda}    

{\lambda}=0.354\times 10^{-6}m=354nm     (1nm=10^{-9}m

Thus the maximum wavelength is 354 nm

6 0
3 years ago
How many grams of ammonium chloride (gram formula mass= 53.5 g) are contained in .500 L of a 2.00 M solution?
Elza [17]

Answer:

53.5g of NH4Cl

Explanation:

First, we need to obtain the number of mole of NH4Cl. This is illustrated below:

Volume = 0.5L

Molarity = 2M

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 2 x 0.5

Mole = 1mole

Now, let us convert 1mole of NH4Cl to gram. This is illustrated below:

Molar Mass of NH4Cl = 53.5g/mol

Number of mole = 1

Mass =?

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass = 1 x 53.5

Mass = 53.5g

Therefore, 53.5g of NH4Cl is contained in the solution.

8 0
3 years ago
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