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Nady [450]
3 years ago
10

Stock System naming for NaCl4, SO3, As2F4.

Chemistry
1 answer:
Ostrovityanka [42]3 years ago
6 0
NaCI4: Sodium perchlorate
SO3: SULFITE ION
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Given the molar absorptivity for a species X of 1600 M-1cm-1 at a wavelength of 270 nm, and 400 M-1cm-1 at a wavelength of 540 n
Andre45 [30]

Answer:

Explanation:

From the given information:

At wavelength = 270 nm

\varepsilon x_1 = 1600 \ m^{-1} \ cm^{-1}  \\ \\  \varepsilon y_1 = 200 \ m^{-1} \ cm^{-1}

At 270 nm

Suppose x is said to be the solution for the concentration of x and y to be the solution for the concentration of y;

Then:

\varepsilon x_1  \ l + \varepsilon y_1  \ l= 0.5 \\ \\ A = A_1 + A_2

1600 xl + 200 yl= 0.5

Divide both sides by 200

8xl + yl = \dfrac{0.5}{200}

8x + y = \dfrac{0.5}{200}l

Use l = 1cm (i.e the standard length)

Then;

8x + y = \dfrac{0.5}{200} ---- (1)

<u>For 540 nm:</u>

\varepsilon x_2 x  \ l + \varepsilon y_2 y  \ l= 0.5  \\ \\ 40 xl + 800 yl = 0.5

x + 20 y = \dfrac{0.5}{400 \ l}

since l = 1

x + 20 y = \dfrac{0.5}{400 \ } --- (2)

Equating both (1) and (2) together, we have:

8x + y - 8x - 160 y = \dfrac{0.5}{200} - \dfrac{0.5 \times 8}{400}  \\ \\  \implies - 159 y = \dfrac{0.5}{200} ( 1 - \dfrac{8}{2}) \\ \\  -159 y = \dfrac{-0.5 \times 3}{200}  \\ \\  159 \ y = 0.0075  \\ \\  y = \dfrac{0.0075}{159} \\ \\  y = 0.00004716 \\ \\ y = 4.7 \times 10^{-5 } \ M

3 0
3 years ago
Oxidation states of NaMnO4
k0ka [10]
I have written it out and explained it. I hope it helps! Here:

7 0
3 years ago
What is the specific activity (in Bq/g) if 1.07 kg of an isotope emits 3.77X10⁷β⁻ particles per minute?
raketka [301]

Specific activity is the activity per unit mass of a radionuclide and is a physical property of that radionuclide. Activity is a quantity (for which the SI unit is the becquerel) related to radioactivity, and is defined as the number of radioactive transformations per second that occur in a particular radionuclide.

How do you find the specific activity of an isotopes?

  •          Activity = λN.
  •          = (0.693/8 days) x (1/86,400 sec/day) x (3 x 1017 atoms)
  •          = 3 x 1011 atoms/sec I-131.
  •          = 3 x 1011 dps I-131.

<h3>What is the specific activity of Co 60?</h3>

The average specific activity of 60Co in continental aquatic sediments is in the region of 1 Bq. kg-1 dry weight (Eyrolle et al., 2008). Cobalt distribution in the abiotic compartments of continental aquatic systems is characterised by the strong affinity of the element for sediment.

Learn more about specific activity of isotopes here:

<h3>brainly.com/question/364529</h3><h3 /><h3>#SPJ4</h3>
3 0
1 year ago
Butters can jump 5.5 feet. How many inches can he jump? (12 in = 1 ft)
olchik [2.2K]

Answer:66

Explanation:

5.5 feet is 66 inches

7 0
3 years ago
Read 2 more answers
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
Inessa [10]

Answer:

The answer is "\bold{4.97 \times 10^{-2}}"

Explanation:

Please find the complete question in the attached file.

Equation:

2SO_2+O_2  \leftrightharpoons 2SO_3

at t=0 3.3   \ \ \ \ \ \ \ \ \ \ 0.79

at equilibrium 3.3-p \ \ \ \ \ \ \ \ \ \ 0.79 - \frac{P}{2} \ \ \ \ \ \ \ \ \ \ \ \ P

p= 0.47 \ \ atm\\\\SO_2=3.3-0.47 = 2.83 \ \ atm\\\\O_2= 0.74 -\frac{0.47}{2}=0.74-0.235=0.555 \ atm\\\\K_P=\frac{[PSO_3]^2}{[PSO_2]^2[PO_2]}\\\\

     =\frac{0.47^2}{2.83^2\times 0.555}\\\\=4.97 \times 10^{-2}

8 0
3 years ago
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