Answer:
Explanation:
From the given information:
At wavelength = 270 nm

At 270 nm
Suppose x is said to be the solution for the concentration of x and y to be the solution for the concentration of y;
Then:


Divide both sides by 200


Use l = 1cm (i.e the standard length)
Then;

<u>For 540 nm:</u>


since l = 1

Equating both (1) and (2) together, we have:

I have written it out and explained it. I hope it helps! Here:
Specific activity is the activity per unit mass of a radionuclide and is a physical property of that radionuclide. Activity is a quantity (for which the SI unit is the becquerel) related to radioactivity, and is defined as the number of radioactive transformations per second that occur in a particular radionuclide.
How do you find the specific activity of an isotopes?
- Activity = λN.
- = (0.693/8 days) x (1/86,400 sec/day) x (3 x 1017 atoms)
- = 3 x 1011 atoms/sec I-131.
- = 3 x 1011 dps I-131.
<h3>What is the specific activity of Co 60?</h3>
The average specific activity of 60Co in continental aquatic sediments is in the region of 1 Bq. kg-1 dry weight (Eyrolle et al., 2008). Cobalt distribution in the abiotic compartments of continental aquatic systems is characterised by the strong affinity of the element for sediment.
Learn more about specific activity of isotopes here:
<h3>
brainly.com/question/364529</h3><h3 /><h3>#SPJ4</h3>
Answer:
The answer is "
"
Explanation:
Please find the complete question in the attached file.
Equation:
at
at equilibrium
![p= 0.47 \ \ atm\\\\SO_2=3.3-0.47 = 2.83 \ \ atm\\\\O_2= 0.74 -\frac{0.47}{2}=0.74-0.235=0.555 \ atm\\\\K_P=\frac{[PSO_3]^2}{[PSO_2]^2[PO_2]}\\\\](https://tex.z-dn.net/?f=p%3D%200.47%20%5C%20%5C%20atm%5C%5C%5C%5CSO_2%3D3.3-0.47%20%3D%202.83%20%5C%20%5C%20atm%5C%5C%5C%5CO_2%3D%200.74%20-%5Cfrac%7B0.47%7D%7B2%7D%3D0.74-0.235%3D0.555%20%5C%20atm%5C%5C%5C%5CK_P%3D%5Cfrac%7B%5BPSO_3%5D%5E2%7D%7B%5BPSO_2%5D%5E2%5BPO_2%5D%7D%5C%5C%5C%5C)
