Answer:
the total density of the mixture = 3.415 x 10^3 g/mL
Explanation:
given:
density of a substance is 3.4 x 10^3 g/mL
Mixing it with another substance increases the density by 1.5 x 10^1 times.
find:
What is the density of the mixture?
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let density (a) = 3.4 x 10^3 g/mL
density(b) = 1.5 x 10^1 g/mL
since there is no specific density provided for the mixture, we then add both to increase the density,
total density = density(a) + density(b)
total density = 3.4 x 10^3 g/mL + 1.5 x 10^1 g/mL
total density = 3.415 x 10^3 g/mL
therefore,
the total density of the mixture = 3.415 x 10^3 g/mL
Answer: 0.67 ml
Explanation:
According to the dilution law,
where,
= concentration of stock solution = 226 mg/ml
= volume of stock solution = ?
= concentration of working solution= 15 mg/ml
= volume of working solution= 10 ml
Putting in the values we get:
Thus volume of stock solution needed to dilute to have 10mL of working solution at the above concentration is 0.67 ml
<span>When refrigerants are mixed, somebody must recover the mixture into a separate </span><span>container or tank.
</span>Refrigerant<span> is a mixture,</span> that can transform from liquid to gas and vice versa. Refrigerants <span>used in a </span>heat pump and refrigerators. They <span>should not be mixed together, one of the reason is because they are flammable.</span>
Answer:
The answer to your question is 900 g of water vapor
Explanation:
Data
mass of H₂O = ?
mass of butane = 580 g
Balanced chemical reaction
2C₄H₁₀ + 13O₂ ⇒ 8CO₂ + 10H₂O
Process
1.- Calculate the molar weight of butane and water
Butane (C₄H₁₀) = 2[(12 x 4) + (1 x 10)]
= 2[48 + 10]
= 2[58]
= 116 g
Water (H₂O) = 10[(1 x 2) + (1 x 16)]
= 10[2 + 16]
= 10[18]
= 180 g
2.- Use proportions and cross multiplication to find the mass of water vapor
116 g of butane ------------- 180 g of water
580 g of butane ---------- x
x = (580 x 180) / 116
x = 900 g of water vapor
Answer:
B) It will increase.
Explanation:
Solubility tends to increase with an increase in temperature
