Answer:
By using renewable energy sources.
Explanation:
You need to satisfy a quota of energy for (whatever country you live in). People do this by using the cheapest way of producing the most energy, the most efficient. Sounds great right? Wrong! It stuffs our atmosphere with harmful gasses like carbon dioxide. You can reduce the use of these fossil fuels by using renewable energy sources such as windmills, watermills, and most notable, solar panels!
The average atomic mass of Sn is 118.71 g/mol
the percentage of heaviest Sn is 5.80%
the given mass of Sn is 82g
The total moles of Sn will be = mass / atomic mass = 82/118.71=0.691
Total atoms of Sn in 82g = 
the percentage of heaviest Sn is 5.80%
So the total atoms of
= 5.80% X 
Total atoms of
=
atoms
the mass of
will be = 
Answer:
there are 2 V's and there are 5 O's
Explanation:
Answer:
26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.
Explanation:
Molar mass of compound = 120 g/mol
Number of sulfur atom = 1
Atomic mass of sulfur = 32 g/mol
Percentage of element in compound :

Sulfur :

26.7% is the percent composition by mass of sulfur in a compound named magnesium sulfate.
To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:
45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present
Hope this answers the question. Have a nice day.