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JulijaS [17]
3 years ago
5

Theresa earned scores of 88 points, 84 points, 88 points, and 91 points on four tests. What is the lowest score she can get on t

he fifth test and still finish with an average score of 90 points?
Mathematics
2 answers:
PIT_PIT [208]3 years ago
5 0
Let x represent her score on the next test. 88, 84, 88, 91, and x are 5 scores Take the sum of those numbers and divide by 5 Set that expression equal to 90. Solve for x to find the lowest score she can make and have an average of 90.
Leokris [45]3 years ago
3 0

Answer:

99 points

Step-by-step explanation: it is just trust me

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Fill in your answers below with proper labels (words written out). Use π=3.14 Diameter = (number) (label in words) Radius = (num
il63 [147K]

Answer:

Step-by-step explanation:

Diameter:

A line passing through the center of the circle touching the circle at two points, is called diameter.

OR

The chord passing through the center is diameter.

It is double of the radius.

so,

Diameter = (2) (Radius of the circle)

Radius:

Diameter divided by 2.

OR half of the diameter is called radius.

So,

Radius = (1/2) (diameter of the circle)

Area of a circle:

Area of a circle =πr^2

Using π=3.14

Area ≈ (3.14) (radius squared)

Circumference of a cricle:

It is equal to 2πr

If π=3.14, then 2π=6.28

Circumference ≈ (6.28) (radius of the circle)

5 0
3 years ago
Prove that, tan θ ( 1 + cot ^ 2 θ ) / ( 1 + tan ^ 2 θ ) = cot θ
Gekata [30.6K]

Answer:

(identity has been verified)

Step-by-step explanation:

Verify the following identity:

tan(θ) (cot(θ)^2 + 1)/(tan(θ)^2 + 1) = cot(θ)

Multiply both sides by tan(θ)^2 + 1:

tan(θ) (cot(θ)^2 + 1) = ^?cot(θ) (tan(θ)^2 + 1)

(cot(θ)^2 + 1) tan(θ) = tan(θ) + cot(θ)^2 tan(θ):

tan(θ) + cot(θ)^2 tan(θ) = ^?cot(θ) (tan(θ)^2 + 1)

cot(θ) (tan(θ)^2 + 1) = cot(θ) + cot(θ) tan(θ)^2:

tan(θ) + cot(θ)^2 tan(θ) = ^?cot(θ) + cot(θ) tan(θ)^2

Write cotangent as cosine/sine and tangent as sine/cosine:

sin(θ)/cos(θ) + sin(θ)/cos(θ) (cos(θ)/sin(θ))^2 = ^?cos(θ)/sin(θ) + cos(θ)/sin(θ) (sin(θ)/cos(θ))^2

(sin(θ)/cos(θ)) + (cos(θ)/sin(θ))^2 (sin(θ)/cos(θ)) = cos(θ)/sin(θ) + sin(θ)/cos(θ):

cos(θ)/sin(θ) + sin(θ)/cos(θ) = ^?(cos(θ)/sin(θ)) + (cos(θ)/sin(θ)) (sin(θ)/cos(θ))^2

(cos(θ)/sin(θ)) + (cos(θ)/sin(θ)) (sin(θ)/cos(θ))^2 = cos(θ)/sin(θ) + sin(θ)/cos(θ):

cos(θ)/sin(θ) + sin(θ)/cos(θ) = ^?cos(θ)/sin(θ) + sin(θ)/cos(θ)

The left hand side and right hand side are identical:

Answer: (identity has been verified)

3 0
3 years ago
Piece function:
Nimfa-mama [501]

First, make the table so you can sketch the graph:

    x   |    y

    5  |   20        

    4  |    9              x² - 5   ; x > 3

 <u>   3  |    </u><u>4 </u><u>  </u><u><em>(open dot)                      </em></u><em>   ⇒ </em>from the right

  <u>  3  |    </u><u>5</u><u>                  5     ; x = 3       </u>   ⇒ at x = 3

    3  |    2  <em>(open dot)                          ⇒ </em>from the left

    2  |    4              -2x + 8  ; x < 3          

<u>     1   |    6                                           </u>


Next, look at the graph (or table) to find the limits:

lim 3⁺ = 4  <em>as x approaches 3 from the right, y approaches 4</em>

lim 3⁻ = 2  <em>as x approaches 3 from the left, y approaches 2</em>

lim 3 = DNE <em>lim 3⁺ ≠ lim 3⁻ so the limit does not exist</em>

f(3) = 5  <em>when x = 3, y = 5</em>

f(x) is NOT continuous at x = 3 <em>because lim 3 ≠ f(3)</em>

5 0
3 years ago
Pleaseeeeeeeeeeeeeeeeeee help
NikAS [45]

Answer:

2x-7

-14

3x

x = 1

Step-by-step explanation:

4 0
3 years ago
Which of these numbers is a common factor of 54 and 81? 54 = 2 x 3 x 3 x 3 81 = 3 x 3 x 3 x 3 A) 2 B) 6 C) 9 D) 18
stealth61 [152]

Answer:

C) 9

Step-by-step explanation:

54 = 2 x 3 x 3 x 3

81 = 3 x 3 x 3 x 3

common factor of 54 and 81 = 3 x 3 = 9

Answer: 9

6 0
3 years ago
Read 2 more answers
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