Answer:
Pressure of O₂ = 0.93 atm
Pressure of krypton = 3.32 atm
Explanation:
This problem can be solved by using Dalton's Law of Partial Pressures, which states that the partial pressure of a component of a gaseous mixture depends on the mole ratio of said component and the total pressure of the gaseous mixture.
Pₐ = Xₐ * Ptotal
P
ₐ - the partial pressure of component a
χ
ₐ - its mole fraction in the mixture
P
total - the total pressure of the mixture
The moles of the two gases are:
moles of O₂ = 11.2/32 = 0.35 moles
moles of krypton = 104.75/83.8 = 1.25 moles
Total moles = 1.25 + 0.35 = 1.6 moles
Xₐ = number of moles of a /total moles in mixture
Pressure of O₂ = 0.35/1.6 *4.25 = 0.93 moles
Pressure of krypton = 1.25/1.6 *4.25 = 3.32 moles
Answer:
i guess its example of observation
Answer:
The red arrow from igneous to sedimentary rock
Explanation:
When rocks are weathered and eroded, they become sediment. This sediment is later compacted and cemented to form sedimentary rock. Therefore, the red arrow going from igneous rock to sedimentary rock represents weathering and erosion.
Answer : The 
for this reaction is, -88780 J/mole.
Solution :
The balanced cell reaction will be,
Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.
The half oxidation-reduction reaction will be :
Oxidation : 
Reduction : 
Now we have to calculate the Gibbs free energy.
Formula used :
where,
= Gibbs free energy = ?
n = number of electrons to balance the reaction = 2
F = Faraday constant = 96500 C/mole
= standard e.m.f of cell = 0.46 V
Now put all the given values in this formula, we get the Gibbs free energy.
Therefore, the for this reaction is, -88780 J/mole.
