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dolphi86 [110]
3 years ago
12

Is Oxygen - O2 a pure substance or a mixture?

Chemistry
1 answer:
svetlana [45]3 years ago
5 0
Oxygen is a pure substance, as it is composed of only a single kind of atom. Which is the oxygen atom, it cannot be broken or degraded down any further into constituents that make up the element. In terms of both chemically and physically.
You might be interested in
If you want 2 miles of Silver (Ag) from the reaction below, how many grams of copper should you start with? Reaction: Cu + 2AgNO
RSB [31]

Answer:

You should start with 63.54 grams of copper.

Explanation:

The chemical reactions are processes in which the nature of the substances changes, that is, from some initial substances called reactants, totally different ones called products are obtained.

In the chemical reaction, the formulas of reagents and products appear preceded by numbers (the stoichiometric coefficients) that indicate the proportions according to which the transformation occurs. So you can say that stoichiometry establishes relationships between the molecules or elements that make up the reactants of a chemical equation with the products of said reaction. The relationships that are established are MOLAR relationships between the compounds or elements that make up the chemical equation: always in MOLES.

The stoichiometric coefficients of a chemical equation are due to the fact that the atoms present before the reaction must be the same after the reaction, although they will have been rearranged to produce new substances.

If you want 2 moles of silver (Ag), for stoichiometry of the reaction you need a moles of copper Cu. Being the molar mass of copper Cu 63.54 g / mole, then:

1 mole*63.54 g/mole= 63.54 g

<u><em> You should start with 63.54 grams of copper.</em></u>

<u><em></em></u>

8 0
3 years ago
what is the mass (in grams) of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride?
Gnoma [55]

The mass of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride is 15.26 g.

The balanced chemical reaction is :

<em>            2Na + Cl₂ → 2NaCl</em>

<em />

Given data :

Mass of sodium = 10.0 g

Number of moles of Na -

Number of moles = <u>  Given mass  </u>

                                    Molar mass

Number of moles = <u> 10.0 g</u> = 0.43 mol

                                  23 g

Comparing moles of Na and Cl₂ from the balanced chemical equation,

                                            Na        :        Cl₂

                                             2          :         1

                                             0.43     :        <u> 1 </u> x 0.43 = 0.215 mol

                                                                   2

Mass of chlorine gas :

          (molar mass of chlorine = 71 g)

Mass of chlorine = number of moles x molar mass

Mass = 0.215 mol x 71 g/mol

          = 15.26 g

To learn more about sodium and chlorine,

brainly.com/question/14588368

#SPJ4

7 0
1 year ago
What is an example of a scope three carbon emission?
MAXImum [283]

Production of materials and transportation are the examples of three carbon emission.

Extraction and production of purchased materials and transportation of purchased fuels are the examples of three carbon emission. Scope 3 emissions refers to all indirect emissions that occur in the chain of the reporting company that is included in both upstream and downstream emissions.

Big machineries are used for the production and extraction of materials as well as the transportation requires fossil fuels for working which releases carbondioxide gas in the atmosphere so we can conclude that production of materials and transportation are the examples of three carbon emission.

5 0
3 years ago
Nitric oxide reacts with chlorine to form nocl. the data refer to 298 k. 2no(g) + cl2(g) → 2nocl(g) substance: no(g) cl2(g) nocl
tigry1 [53]

Answer:

- 10.555 kJ/mol.

Explanation:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

Where, ∆G°rxn is the standard free energy change of the reaction (J/mol).

∆H°rxn is the standard enthalpy change of the reaction (J/mol).

T is the temperature of the reaction (K).

∆S°rxn is the standard entorpy change of the reaction (J/mol.K).

  • Calculating ∆H°rxn:

∵ ∆H°rxn = ∑∆H°products - ∑∆H°reactants

<em>∴ ∆H°rxn = (2 x ∆H°f NOCl) - (1 x ∆H°f Cl₂) - (2 x ∆H°f NO) </em>= (2 x 51.71 kJ/mol) - (1 x 0) - (2 x 90.29 kJ/mol) = - 77.16 kJ/mol.

  • Calculating ∆S°rxn:

∵  ∆S°rxn = ∑∆S°products - ∑∆S°reactants

<em>∴ ∆S°rxn = (2 x ∆S° NOCl) - (1 x ∆S° Cl₂) - (2 x ∆S° NO) </em>= (2 x 261.6 J/mol.K) - (1 x 223.0 J/mol.K) - (2 x 210.65 J/mol.K) =<em> - 121.1 J/mol.K. = - 0.1211 kJ/mol.K.</em>

<em></em>

  • Calculating ∆G°rxn:

∵ ∆G°rxn = ∆H°rxn - T∆S°rxn.

<em>∴ ∆G°rxn = ∆H°rxn - T∆S°rxn </em>= (- 77.16 kJ/mol) - (550 K)(- 0.1211 kJ/mol.K) = <em>- 10.555 kJ/mol.</em>

4 0
3 years ago
19.5 g O2 is equal to how many moles of O2? _____moles O2
vredina [299]

Explanation:

Molar mass of O2: 32g/mol

Moles of O2 = 19.5 / 32 = 0.609mol

8 0
3 years ago
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