The length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.
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Length of the entire hydrogen atoms</h3>
The length of the entire hydrogen atom is calculated as follows;
Length of the row = number x diameter of one
Length of the row = 4.34 x 10²³ x 10⁶ x 10⁻¹²
Length of the row = 4.34 x 10¹⁷ m
Length of the row = 4.34 x 10¹⁴ km
Thus, the length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.
Learn more about diameter of hydrogen atom here: brainly.com/question/13796082
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It makes it thinner to calcite the rhythm
Answer:
The answer to your question is: letter B.
Explanation:
Carbon atom double-bonded to an oxygen atom C= O,
a) Carbohydrate group this group does not exist
b)Carbonyl group This option is right, carbonyl group is C=O
c) Hydroxyl group This option is incorrect, hydroxyl group is OH, very different from C=O
d) Ketone group Ketone group does not exist, ketones have the same functional group as aldehydes (C=O)
Complete question:
The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.44×10⁻⁴ s⁻¹ at a certain temperature.
If the initial concentration of SO2Cl2 is 0.125 M , what is the concentration of SO2Cl2 after 210 s ?
Answer:
After 210 s the concentration of SO2Cl2 will be 0.121 M
Explanation:
![ln\frac{[A_t]}{[A_0]} =-kt](https://tex.z-dn.net/?f=ln%5Cfrac%7B%5BA_t%5D%7D%7B%5BA_0%5D%7D%20%3D-kt)
where;
At is the concentration of A at a time t
A₀ is the initial concentration of A
k is rate constant = 1.44×10⁻⁴ s⁻¹
t is time
ln(At/A₀) = -( 1.44×10⁻⁴)t
ln(At/0.125) = -( 1.44×10⁻⁴)210
ln(At/0.125) = -0.03024

At/0.125 = 0.9702
At = 0.125*0.9702
At = 0.121 M
Therefore, after 210 s the concentration of SO2Cl2 will be 0.121 M
Explanation:
Group 16 elements are oxygen family elements also called as chalcogens.This name is given for the their ore forming abilities. It consists of the elements oxygen, sulfur, selenium, tellurium and polonium.
Group 16 have six electron in the outermost principal energy level or the valence shell and their general electronic configuration is ns2 and np4.