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3 years ago

12

Is Oxygen - O2 a pure substance or a mixture?

1 answer:

svetlana [45]3 years ago

5 0

Oxygen is a pure substance, as it is composed of only a single kind of atom. Which is the oxygen atom, it cannot be broken or degraded down any further into constituents that make up the element. In terms of both chemically and physically.

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Using the simulation, how can you show that it takes more energy to convert a liquid to a gas than a solid to a liquid?

icang [17]

Answer:

The enthalpy of vaporization of a given substance is much greater than its enthalpy of fusion because it takes more energy to completely separate molecules (c

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2 years ago

hey guys, i found this marble outside and covered in grease. so i took it in to wash it. can you please tell me what it is made

Scilla [17]

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3 years ago

What is the frequency of the light with a wavelength of 4.90x10^-7 m

docker41 [41]

Answer: $6.12\times 10^{14}$ Hz

Explanation: Recall the formula for the speed of light is

$c=\lambda v$

where $c$ is the speed of light, $\lambda$ is the wavelength, and $v$ is the frequency. Assuming this takes place in a vacuum, $c=3.00\times 10^8$ m/s. Now we can solve for frequency

$c=\lambda v$

$3.00\times 10^8 = 4.90\times 10^{-7}\cdot v$

$v = \frac{3.00\times 10^8}{4.90\times 10^{-7}}$

$v =6.12\times 10^{14}$ (rounding to 3 sig figs)

Thus, the frequencyis $6.12\times 10^{14}$ Hz.

6 0

3 years ago

In an ecosystem, which of the following is NOT an abiotic factor

Oksana_A [137]

Algae is not an abiotic factor.

4 0

3 years ago

What is the expected freezing point of a solution containing 85.0g NaCl dissolved in 450g of water

sattari [20]

The expected freezing point of the solution is -12.01 °C

<h3>What is the freezing point of a substance?</h3>

The freezing point of a substance is the temperature at which a liquid changes to a solid.

When solutes are dissolved in solvents, they depress the freezing point of the solvent.

The expected freezing point of the solution is calculated using the formula;

ΔT = K * m * i

where:

ΔT = freezing point depression
K = Freezing point constant
m = molality of the solution
i = Van't Hoff factor

For water, K = 1.86 ∘c/m

molality of solution = moles of solute/ mass of water in Kg

moles of NaCl = 85/58.5 = 1.453 moles

mass of water in kg = 450/1000 = 0.45

molality of solution = 1.453 / 0.45

molality of solution = 3.23 molal

i = 2

ΔT = 1.86 × 3.23 × 2

ΔT = 12.01

Freezing point of solution = Freezing point of water - ΔT

Freezing point of solution = 0 - 12.01

Freezing point of solution = -12.01 °C

Learn more about freezing point at: brainly.com/question/28182670

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8 0

1 year ago