Answer:
You would use a bar graph
F = G mM / r^2, where
<span>F = gravitational force between the earth and the moon, </span>
<span>G = Universal gravitational constant = 6.67 x 10^(-11) Nm^2/(kg)^2, </span>
<span>m = mass of the moon = 7.36 × 10^(22) kg </span>
<span>M = mass of the earth = 5.9742 × 10^(24) and </span>
<span>r = distance between the earth and the moon = 384,402 km </span>
<span>F </span>
<span>= 6.67 x 10^(-11) * (7.36 × 10^(22) * 5.9742 × 10^(24) / (384,402 )^2 </span>
<span>= 1.985 x 10^(26) N</span>
Passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.
<h3>What is force of inertia?</h3>
Force of inertia is the force which acts in the opposite direction of the force of acceleration acting on the body.
Given infroamtion-
The passengers are facing forward in the direction that the train is moving.
The train comes to a sudden stop.
Lets see what happens step wise-
- Here, the train in moving in the forward direction and the passengers are also facing forward in the direction that the train is moving.
- Now the train comes to a sudden stop. By this sudden stop the train stops suddenly but all the object including the passengers is still travelling forward due to the inertia force.
- Thus all the passenger will tend to move in the direction as they are still travelling.
Hence, passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.
Learn more about the force of inertia here;
brainly.com/question/10454047
Answer:
7kgm/s
Explanation:
Using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.
Let P1A and P1B be the initial momentum of the bodies A and B respectively
Let P2A and P2B be the final momentum of the bodies A and B respectively after collision.
Based on the law:
P1A+P2A = P1B + P2B
Given P1A = 5kgm/s
P2A = 0kgm/s(ball B at rest before collision)
P2A = -2.0kgm/s (negative because it moves in the negative x direction)
P2B = ?
Substituting the values in the equation gives;
5+0 = -2+P2B
5+2 = P2B
P2B = 7kgm/s