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klemol [59]
3 years ago
11

For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vec

tors? For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vectors? a) The velocity vector is perpendicular to the acceleration vector; the acceleration vector is perpendicular to the net force vector. b) The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector. c) The velocity vector is parallel to the acceleration vector; the acceleration vector is perpendicular to the net force vector. d) The velocity vector is parallel to the acceleration vector; the acceleration vector is parallel to the net force vector.
Physics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer: b) The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector.

Explanation: A change in velocity creates an acceleration. As the object rotates through the circular path it is constantly changing direction, and hence accelerating, which causes a constant force to act upon the object. This Force acts towards the center of curvature, directly toward the axis of rotation in a direction parallel to the acceleration of the body along the path. Because the object is moving perpendicular to the force, the path followed by the object is a circular one. Hence the velocity of the object is perpendicular to the acceleration.

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Neil Armstrong

Explanation:

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Calculate the magnitude of the average gravitational force between earth and the moon
zepelin [54]
F = G mM / r^2, where 
<span>F = gravitational force between the earth and the moon, </span>
<span>G = Universal gravitational constant = 6.67 x 10^(-11) Nm^2/(kg)^2, </span>
<span>m = mass of the moon = 7.36 × 10^(22) kg </span>
<span>M = mass of the earth = 5.9742 × 10^(24) and </span>
<span>r = distance between the earth and the moon = 384,402 km </span>

<span>F </span>
<span>= 6.67 x 10^(-11) * (7.36 × 10^(22) * 5.9742 × 10^(24) / (384,402 )^2 </span>
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5 0
3 years ago
The passengers are facing forward in the direction that the train is moving. What will happen to the passengers sitting on a tra
marysya [2.9K]

Passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.

<h3>What is force of inertia?</h3>

Force of inertia is the force which acts in the opposite direction of the force of acceleration acting on the body.

Given infroamtion-

The passengers are facing forward in the direction that the train is moving.

The train comes to a sudden stop.

Lets see what happens step wise-

  • Here, the train in moving in the forward direction and the passengers are also facing forward in the direction that the train is moving.

  • Now the train comes to a sudden stop. By this sudden stop the train stops suddenly but all the object including the passengers is still travelling forward due to the inertia force.

  • Thus all the passenger will tend to move in the direction as they are still travelling.

Hence, passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.

Learn more about the force of inertia here;

brainly.com/question/10454047

6 0
2 years ago
g A lighter ball A with momentum PA=5.0 kg∙m/s in positive x-direction approaches a heavier ball B at rest before the collision.
Svet_ta [14]

Answer:

7kgm/s

Explanation:

Using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Let P1A and P1B be the initial momentum of the bodies A and B respectively

Let P2A and P2B be the final momentum of the bodies A and B respectively after collision.

Based on the law:

P1A+P2A = P1B + P2B

Given P1A = 5kgm/s

P2A = 0kgm/s(ball B at rest before collision)

P2A = -2.0kgm/s (negative because it moves in the negative x direction)

P2B = ?

Substituting the values in the equation gives;

5+0 = -2+P2B

5+2 = P2B

P2B = 7kgm/s

3 0
3 years ago
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