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klemol [59]
3 years ago
11

For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vec

tors? For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vectors? a) The velocity vector is perpendicular to the acceleration vector; the acceleration vector is perpendicular to the net force vector. b) The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector. c) The velocity vector is parallel to the acceleration vector; the acceleration vector is perpendicular to the net force vector. d) The velocity vector is parallel to the acceleration vector; the acceleration vector is parallel to the net force vector.
Physics
1 answer:
zavuch27 [327]3 years ago
3 0

Answer: b) The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector.

Explanation: A change in velocity creates an acceleration. As the object rotates through the circular path it is constantly changing direction, and hence accelerating, which causes a constant force to act upon the object. This Force acts towards the center of curvature, directly toward the axis of rotation in a direction parallel to the acceleration of the body along the path. Because the object is moving perpendicular to the force, the path followed by the object is a circular one. Hence the velocity of the object is perpendicular to the acceleration.

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what is the net force on an object that is experiencing a force of 25 N north, a force of 25 N south, a force of 50 N to the eas
REY [17]

Answer:

5 n

Explanation:

25 and 25 cancel each other out and 50-45 is 5

4 0
3 years ago
A 70-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m,
Tems11 [23]

Answer:

3.6 KJ

Explanation: Given that a 70-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m, and ends with a speed of 8.5 m/s. How much nonconservative work (in kJ) was done on the boy

The workdone = the energy.

There are two different energies in the scenario - the potential energy (P.E ) and the kinetic energy ( K.E )

P.E = mgh

P.E = 70 × 9.8 × 1.6

P.E = 1097.6 J

P.E = 1.098 KJ

K.E = 1/2mv^2

K.E = 1/2 × 70 × 8.5^2

K.E = 2528.75 J

K.E = 2.529 KJ

The non conservative workdone = K.E + P.E

Work done = 1.098 + 2.529

Work done = 3.63 KJ

Therefore, the non conservative workdone is 3.6 KJ approximately

5 0
2 years ago
Compared with those who live in the lowlands, people who live in the Southeast highlands experience​
Alisiya [41]

Answer:

The territory of Scotland was divided into two parts -- the highlands and the lowlands.

Explanation:

The people living in places of high altitudes are called highlanders. These high altitude places are called high lands and places with low elevations or altitudes are called the low lands. There are many differences between the two places and people experiences different difficulties in these places.

Some of the differences are :

The life of the people living in high lands are much more tougher than those living in the low lands. The highlanders have to work more hard than lowlanders.

The agricultural activities are more flourished in the low lands than in the high lands.

The low lands are more populated and highly industrialized than the high lands. Iron and steel industry, metal working industry and agriculture are some of the main industries of lowlands. They are the land of the Scottish nation.

6 0
2 years ago
1. What does the endocrine system have in common with the muscular system?
Lostsunrise [7]

Answer:

B Both are directly related to movement.

7 0
3 years ago
Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula KE = mv2, where m is t
Aliun [14]

kinetic energy is given as

KE = (0.5) m v²

given that : v = speed of the bottle in each case =  4 m/s

when m = 0.125 kg

KE = (0.5) m v² =  (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg

KE = (0.5) m v² =  (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg

KE = (0.5) m v² =  (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg

KE = (0.5) m v² =  (0.5) (0.500) (4)² = 4 J

6 0
2 years ago
Read 3 more answers
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