Anna applies a force of 19.5 newtons to push a book placed on a table. If the normal force of the book is 51.7 newtons, what is

Question

Lynna [10]

3 years ago

10

Anna applies a force of 19.5 newtons to push a book placed on a table. If the normal force of the book is 51.7 newtons, what is

the coefficient of kinetic friction?

Physics

2 answers:

andrey2020 [161] · Answer 1 · 2022-07-16T13:47:03+03:00

andrey2020 [161]3 years ago

5 0

Considering that the book is moving with constant speed, the force applied by Anna must be the same that the friction force:

$F = F_R = F\cdot \mu_k\cdot N$

If we clear the previous equation:

$\mu_k = \frac{F}{F_R} = \frac{19.5\ N}{51.7\ N} = \bf 0.38$

barxatty [35] · Answer 2 · 2022-07-16T15:14:06+03:00

The force applied to the book is equal to the normal force of the book multiplied by the coefficient of kinetic friction. <span>The normal force is equal to the weight of the book. </span>In this case, the formula with the given data is equal to 19.5N = 51.7N * coeff. of friction. The coefficient of friction is equal to 0.38.