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kogti [31]
3 years ago
8

An electron, starting from rest, accelerates through a potential difference of 40.0 V. What is the final de Broglie wavelength o

f the electron, assuming that its final speed is not relativistic?
Physics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

1.94 x 10^-10 m

Explanation:

V = 40 V

The relation for the de broglie wavelength and teh potential difference is given by

\lambda = \frac{12.27}{\sqrt{V}} Angstrom

\lambda = \frac{12.27}{\sqrt{40}} Angstrom

λ = 1.94 Angstrom = 1.94 x 10^-10 m

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technically usually the warmer object/substances particles move master which causes friction among the particles plus the kinetic energy being converted to thermal energy, so i would say the hand.

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Define homeostasis please I need help
son4ous [18]
Homeostasis is the tendency toward a relatively stable equilibrium between interdependent elements, especially as maintained by physiological processes. 
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please help me guys please please please please please please please please please please please please please​
seropon [69]

Answer:

1.F = 256 N

2.a = 8 m/s/s

By looking at the given information, you know force, and an acceleration. Therefore you have enough information to use the first formula.

F = ma

256 N = m * 8 m/s/s

m = 256 N/8 m/s/s

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6 0
3 years ago
A simple harmonic oscillator consists of a block (m = 0.50 kg) attached to a spring (k = 128 N/m). The block is pulled a certain
Zinaida [17]

Answer:

0.5 m

14.00595

8 m/s, 0.0625 s

5.71314 m/s

Explanation:

k = Spring constant = 128 N/m

A = Amplitude

E = Energy in spring = 16 J

Energy in spring is given by

E=\dfrac{1}{2}kA^2\\\Rightarrow A=\sqrt{\dfrac{2E}{k}}\\\Rightarrow A=\sqrt{\dfrac{2\times 16}{128}}\\\Rightarrow A=0.5\ m

The amplitude is 0.5 m

Time period is given by

T=2\pi\sqrt{\dfrac{m}{k}}\\\Rightarrow T=2\pi\sqrt{\dfrac{0.5}{128}}\\\Rightarrow T=0.39269\ s

Number of oscillations is given by

N=\dfrac{5.5}{0.39269}\\\Rightarrow N=14.00595

The number of oscillations is 14.00595

For maximum speed

\dfrac{1}{2}mv^2=16\\\Rightarrow v=\sqrt{\dfrac{16\times 2}{0.5}}\\\Rightarrow v=8\ m/s

The maximum speed is 8 m/s

For a distance of 0.5 m which is the amplitude

Time=\dfrac{Distance}{Speed}\\\Rightarrow Time=\dfrac{0.5}{8}\\\Rightarrow Time=0.0625\ s

The time taken would be 0.0625 s

The maximum kinetic energy is equal to the mechanical energy

\dfrac{1}{2}mv^2+\dfrac{1}{2}kx^2=16

At x = 0.35 m

v=\sqrt{\dfrac{16-\dfrac{1}{2}kx^2}{\dfrac{1}{2}m}}\\\Rightarrow v=\sqrt{\dfrac{16-\dfrac{1}{2}128\times 0.35^2}{\dfrac{1}{2}0.5}}\\\Rightarrow v=5.71314\ m/s

The speed of the block is 5.71314 m/s

4 0
3 years ago
Read 2 more answers
If you were to apply a force of 15N to a medicine ball with a mass of 10kg, what would its acceleration be
tresset_1 [31]

One of the equations for force is:  Force = mass × acceleration.

The force and mass are given and so:

F=15N

m=10kg

By plugging in these values we obtain:

F=ma\\\\15=10(a)\\

\frac{15}{10}=\frac{10(a)}{10}\\\\a=\frac{15}{10}=1.5m/s^2

So the acceleration is a=1.5m/s^2

6 0
3 years ago
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