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Oksi-84 [34.3K]
4 years ago
15

- 爷爷和奶奶的对话,对故事情节的发展有什么作用​

Chemistry
2 answers:
nika2105 [10]4 years ago
8 0

Answer:爷爷和奶奶的对话, 是从哪里来的. 告诉我, 我先帮你. 是从一书里么.你呢不能给我发一个图片.谢谢.

g100num [7]4 years ago
6 0

Answer:

I think this is under the wrong category.

Explanation:

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How much energy is released when 65.8 g of water freezes
Delvig [45]

The amount of energy released is calculated by the product of heat of fusion and mass. The formula of amount energy released is given by: q= L\times m                (1)

Here,  

q is amount of energy released L is heat of fusion (334 J/g) m is mass of water Put all the given values in equation (1)

q= 334 J/g \times 65.8 g

q= 21977.2 Joules ≅ 21977 Joules

q= 21977 Joules

Thus, amount of energy released is 21977 Joules


6 0
3 years ago
Read 2 more answers
calculate the molarity of MgCl2 in the following solution: 5.34 g of MgCl2 is dissolved and diluted to 214 mL of solution.
anyanavicka [17]
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf {0.262M }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>

Molarity is used to measure the concentration of a solution , so it is also as molar concentration. It is denoted as M or Mol/L

<u>We </u><u>are </u><u>given </u><u>that </u><u>:</u>

  • Weight of \sf MgCl_{2} = 5.34g
  • Volume of solution = 214 ml , or 0.214 L

The molar mass of magnesium chloride ( \sf MgCl_{2} ) is 95.21 g / mol

We can calculate the molarity of the solution by dividing the number of moles of solute by volume of solvent in liter ,i.e:

\quad\longrightarrow\quad \sf  {M = \dfrac{n}{V} } ‎ㅤ‎ㅤ‎ㅤ⸻( 1 )

<em>Where,</em><em> </em>

  • M = molarity
  • n = number of moles
  • V = Volume

We can calculate the number of moles by dividing the actual mass by its molar mass ,i.e:

\quad\longrightarrow\quad \sf { n = \dfrac{w}{m}}‎ㅤ‎ㅤ‎ㅤ‎⸻ ( 2 )

<em>W</em><em>here,</em>

  • n = number of moles
  • m = molar mass
  • w = actual mass

<u>Therefore</u><u>,</u>

\implies\quad \tt {n =\dfrac{w}{m} }

\implies\quad \tt { n =\dfrac{5.35\: g}{95.21\: g /mol}}

\implies\quad{\pmb{ \tt {n = 0.056 mol}} }

<u>P</u><u>utting </u><u>the </u><u>values </u><u>in </u><u>equation </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u>

\implies\quad \tt {M=\dfrac{n}{V} }

\implies\quad \tt { M =\dfrac{0.056\:mol}{0.214\:L}}

\implies\quad\underline{\pmb{ \tt { M = 0.262 \:M }}}

7 0
2 years ago
How many moles of potassium chloride and oxygen can be produced from 100.0g of potassium chlorate? The balanced equation is: 2 K
natka813 [3]

100.0 g KClO₃ × 1 mol KClO₃/122.55 g KClO₃ × 2 mols KCl/2 mols KClO₃= 0.8160 mols of KCl

100.0 g KClO₃ × 1 mol KClO₃/122.55 g KClO₃ × 3 mols O₂/ 2 mols KClO₃= 1.224 mols of O₂

try this

122.55 g is molar mass of potassium chlorate


4 0
3 years ago
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Can yall help with these two questions please thx
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1. True 2. I think A and D. I’m not sure though
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3 years ago
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Without constants you would not know which variable affected the
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Two independent variables could change at the same time, and you would not know which variable affected the dependent variable
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