Answer:
a. H + d. Na
Explanation:
This is Mixture of H and Na. Because of H and in the emission and Absorption spectrum of H Total 5 lines [Red, Green, Blue and Purple (2)) are present and in the spectrum of Na Two yellow lines are present. In the mixture all this lines are are also 5 + Present. Total lines are 5+2= 7 (H+ Na)
Therefore, the answer is a. H + d. Na
Answer:
Smog can be classified as two types. They are
Oxidizing smog
Reducing smog
Oxidizing smog:
The smog which has the property of high concentration of oxidizing agents is known as oxidizing smog. Oxidizing smog can also known as photochemical smog.
Example: Ozone.
Reducing smog:
The smog which has high concentration of sulfur Dioxide is known as reducing smog.Photochemical smog which is very dangerous is called oxidizing smog because it consists of the oxidizing agent ozone.......the other one is reducing smog which consists of reducing agent sulphurdioxide.
Answer:
C-Its product is heavier than each of its reactants.
Explanation:
Correct equation:
¹⁴₇N + ¹₁H → ¹⁵₈O
In the reaction above, we can conclude within the given conditions of the reaction that the product formed is heavier than the reactants.
The product is oxygen with a mass number of 15 as shown by the superscript preceeding the symbol of the atom.
The reactants are:
Nitrogen, N with a mass number of 14
Hydrogen, H with a mass number of 1
The mass number is a true reflection of the mass of an atom. It clearly shows the mass of the nucleons which are the most massive particles that makes up an atom. The nucleons are protons and neutrons that makes up the tiny nucleus of the atom.
Oxygen here has more nucleons that each of Nitrogen and Hydrogen.
Answer:
<h2>leaves,</h2>
Hope it helps....⋋✿ ⁰ o ⁰ ✿⋌(・o・)
Answer:
Basically it would be 8.5g. Not total sure.
Explanation:
If its right plz give brainlest.
